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Debora [2.8K]
2 years ago
13

How many minimum squares are there in a net of a cuboid?

Mathematics
1 answer:
liraira [26]2 years ago
3 0

Answer:  6

There are 6 faces to a cube, so there are 6 squares when you unfold it to form the net of the cube. The net is like the wrapping paper.

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Lateral area is the area of the faces, while surface area is the area of the faces and and bases.
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3 years ago
Find each of these values.
podryga [215]
192=4\cdot41+28\iff192\equiv28\pmod{41}
28=3\cdot9+1\iff28\equiv1\pmod9

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11^2\equiv0\pmod{11}

73=3\cdot23+4\iff73\equiv4\pmod{23}
4^2\equiv16\pmod{31}

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4 0
3 years ago
How many real-number solutions does the equation have?
Dmitrij [34]

Answer:

I'm guessing none because the discrimant (sqrt of b squared - 4ac is less than zero, signifying it has no real roots

Step-by-step explanation:

have a happy holidays!

6 0
3 years ago
Read 2 more answers
A set of X and Y scores has a regression equation with a slope of b = 4. If the mean for the X values is MX = 2 and the mean for
Rom4ik [11]

Answer:

-2

Step-by-step explanation:

In a linear regression model we have the equation Y = b_{1}X + b_{0} that relates X and Y, where b_{1} is the estimator of the slope and b_{0} is the estimator of the Y-intercept. The coefficients b_{1} and b_{0} can be estimated with the equations:

b_{1} = \frac{S_{xy}}{{S^{2}}_{x}}

b_{0} = MY-b_{1}MX. Thus,

b_{0} = 6 - (4)(2) = -2

6 0
3 years ago
Factor f(x)=x4-x3-7x2+13x-6 completely. Then Sketch the graph
Dennis_Churaev [7]

ANSWER TO QUESTION 1


f(x)=(x-2)(x+3)(x-1)^2.



EXPLANATION


The function given to us is,


f(x)=x^4-x^3-7x^2+13x-6


According to rational roots theorem,


\pm1,\pm2,\pm3,\pm6 are possible rational zeros of  


f(x)=x^4-x^3-7x^2+13x-6.


We find out that,


f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6


f(-3)=81+27-63-39-6



f(-3)=6-6



f(-3)=0


Also




f(2)=(2)^4-(2)^3-7(2)^2+13(2)-6



f(2)=16-8-28+26-6



f(2)=6-6



f(2)=0


This implies that  


x-2 and x+3 are factors of



f(x)=x^4-x^3-7x^2+13x-6 and hence (x-2)(x+3)=x^2+x-6 is also a factor.



We perform the long division as shown in the diagram.



Hence,


f(x)=(x-2)(x+3)(x-1)^2.


ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots  

x=2 and x=-3 have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.


Also the root x=1 has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.



Now we determine the position of the graph on the following intervals,


x\le -3


f(-4)=(-4)^4-(-4)^3-7(-4)^2+13(-4)-6


f(-4)=150\:>0



-3\le x \le 1


f(0)=-6\:


1\le x\le 2


f(1.5)=-0.56\:



x \ge 2



f(3)=24\:>0



We can now use these information to sketch the function as shown in diagram



4 0
3 years ago
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