To solve this problem,lets say that
X = the weight of the machine components. <span>
<span>X is normally distributed with mean=8.5 and sd=0.09
We need to find x1 and x2 such that
P(X<x1)=0.03 and P(X>x2)=0.03
<span>Standardizing:
<span>P( Z< (x1 - 8.5)/0.09 ) =0.03
P(Z > (x2 - 8.5)/0.09 ) =0.03.
<span>From the Z standard table, we can see that approximately P
= 0.03 is achieved when Z equals to:</span></span></span></span></span>
<span>z = -1.88 and z= 1.88</span>
Therefore,
P(Z<-1.88)=0.03 and P(Z>1.88)=0.03 <span>
So,
(x1 - 8.5)/0.09 = -1.88 and
(x2 - 8.5)/0.09 =1.88
Solving for x1 and x2:
<span>x1=-1.88(0.09) + 8.5 and
<span>x2=1.88(0.09) + 8.5
<span>Which yields:
<span><span>x1 = 8.33 g</span>
<span>x2 = 8.67 g</span></span></span></span></span></span>
<span>Answer: The bottom 3 is separated by the weight
8.33 g and the top 3 by the weight 8.67 g.</span>
Answer:
b.6,8,10
Step-by-step explanation:
a^2+b^2=c^2
6^2=36
8^2=64
10^2=100
36+64=100
Answer:
1) x^3+4x^2-9x-36
2) not solvable
3)not solvable
4) not solvable
Step-by-step explanation:
how are you supposed to solve these?
Answer:
Explanation:
Let Vc be the velocity of the car and I'm the velocity of the motorcycle. If we convert their given values, we get:
Vc = 87 km/h * 1000m / 1km * 1h / 3600s = 24.17m/s
Vm = 95 km/h * 1000m / 1km * 1h / 3600s = 26.38m/s
Since their positions are equal after 17s we can stablish that:
Where d is the initial separation distance of 54m. Solving for a, we get:
Repacing the values:
