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Katena32 [7]
3 years ago
11

I GIVEEE BRAIUNLILSTT

Mathematics
2 answers:
Charra [1.4K]3 years ago
7 0

Answer:

(x+14,y+8)

Step-by-step explanation:

In the x-axis, each point moves 14 units to the right.

In the y-axis, each point moves 8 units up.

amm18123 years ago
6 0

Answer:

x+13

y+8

sorry if I'm wrong but pretty sure it's right

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Boomer, the dog, eats 3\2​ of dog food each week. How many grams of dog food will Boomer eat in 4weeks?'
sweet [91]

Answer:

6 grams

Step-by-step explanation:

(3/2)*4 = 12/2 = 6

6 0
3 years ago
Read 2 more answers
Suppose that v is an eigenvector of matrix A with eigenvalue λA, and it is also an eigenvector of matrix B with eigenvalue λB. (
galben [10]

Answer:

(a) Yes, λ_{A}+λ_{B}

(b) Yes, λ_{A}λ_{B}

Step-by-step explanation:

First, lets understand what are eigenvectors and eigenvalues?

Note: I am using the notation λ_{A} to denote Lambda(A) sign.

v is an eigenvector of matrix A with eigenvalue λ_{A}

v is also eigenvector of matrix B with eigenvalue λ_{B}

So we can write this in equation form as

Av=λ_{A}v

So what does this equation say?

When you multiply any vector by A they do change their direction. any vector  that is in the same direction as of Av, then this v  is called the eigenvector of A. Av is λ_{A} times the original v. The number λ_{A} is the eigenvalue of A.

λ_{A} this number is very important and tells us what is happening when we multiply Av. Is it shrinking or expanding or reversed or something else?

It tells us everything we need to know!

Bonus:

By the way you can find out the eigenvalue of Av by using the following equation:

det(A-λI)=0

where I is identity matrix of the size of same as A.

Now lets come to the solution!

(a) Show that v is an eigenvector of A + B and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(A+B)(v)=Av+Bv=(λ_{A})v + (λ_{B})v=(λ_{A}+λ_{B})(v)

so,  (A+B)(v)=(λ_{A}+λ_{B})(v)

which means that v is also an eigenvector of A+B and the associated eigenvalues are λ_{A}+λ_{B}

(b) Show that v is an eigenvector of AB and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(AB)(v)=A(Bv)=A(λ_{B})=λ_{B}(Av)=λ_{B}λ_{A}(v)=λ_{A}λ_{B}(v)

so,  

(AB)(v)=λ_{A}λ_{B}(v)

which means that v is also an eigenvector of AB and the associated eigenvalues are λ_{A}λ_{B}

5 0
3 years ago
Let f(x) = - 4x + 5. Find and simplify f(3a-4).<br> f(3a-4)=<br> (Simplify your answer.)
ludmilkaskok [199]

Answer:

-12a+21

Step-by-step explanation:

-4*(3a-4)+5

-12a+16+5

-12a+21

4 0
3 years ago
BRAINLIEST <br> please help And leave just a small explanation and I’ll mark brainliest :)
Reptile [31]

Answer:

A. The value of u should be 115 because the two angles shown in the figure are congruent.

Step-by-step explanation:

You can see the placement of the angles and their relationship, which is corresponding angles. This makes them congruent.

hope this helps! :)

4 0
3 years ago
Read 2 more answers
what is the slope-intercept for of the equation of the line that passes through the point (-6,1) and is perpendicular to the gra
vladimir1956 [14]
The slope that you need to use is 3/2 which is perpendicular to the slope of -2/3.

Use:
y-1=3/2(x+6)
y-1=3x/2 + 9
y=3x/2 + 10

y=3x/2+10 is the final answer
6 0
3 years ago
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