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stellarik [79]
2 years ago
8

Please help I’m so depressed and this is a constant struggle to complete bc I’m online. Will mark Brainlest and thank you! Unit

two lesson six connexues

Mathematics
1 answer:
eduard2 years ago
4 0

Answer: 1 is c and 2 is d

Step-by-step explanation:

you need to use the formula attached (radius is half of diameter)

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Find the next two terms in the sequence 1/3, 1/9,1/27,1/81....
netineya [11]
1/243

each second number is being multiplied by three

3*3=9

9*3=27

27*3=81

so 81*3=243

243 is the answer
3 0
3 years ago
Read 2 more answers
Which steps should be used to graph the equation below? y-4=1/3(x+2)
juin [17]

-> First, we want to put it into more of a slope-intercept form so we can graph.

y - 4 = 1/3 (x + 2)

y = 1/3 (x + 2) + 4

y = 1/3x + 2/3 + 4

y = 1/3x + 14/3

-> Next, we will plot the point (0, 14/3) because it is the y-intercept of our equation

-> Last, we will move up one and to the right three, following the pattern of "rise over run" with our slope of 1/3

       [] The finished graph is attached

       [] I have also graphed the original equation to show that they overlap, showing that our simplification works

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

3 0
2 years ago
The sum of a number and three is less than nineteen less than the number
Nataliya [291]
The answer to the solution is X+3<19-x.

6 0
4 years ago
Solve for x. PLZ HELP ASAP!!!
ycow [4]

X is a vertical angle to the angle marked as 100 degrees.

Vertical angles are the same so x = 100 degrees

Answer: 100 degrees

3 0
4 years ago
What are the degrees of freedom for Student's t distribution when the sample size is 19? d.F. = Use the Student's t distribution
liq [111]

Answer:

a) 18

b) 2.101

Step-by-step explanation:

a) What are the degrees of freedom for Student's t distribution when the sample size is 19?

Degrees of freedom = n - 1

Where n = sample size

= 19 - 1

= 18

b) Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 19.

(Round your answer to three decimal places.)

We would be determining these using the t distribution table

1 - 0.95 = 0.05 ( for two tailed)

Or

0.05/2 = 0.025(one - tailed)

Hence, the tc(test score) for a 0.95 confidence level when the sample is 19 is 2.101

7 0
4 years ago
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