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2 years ago

Four cups of flour make 5/6 batch of bread. How many cups of flour make 1 batch?

Mathematics

1 answer:

melisa1 [442]2 years ago

5 0

Answer:

1 and 1/4ths a cup to make a batch if i worded that right

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8 tins holds 42-2-3 liter of oil. How many liters can 1such tin hold

GarryVolchara [31]

Answer = 4.625

Solution =42-2-3=37

37 divided by 8 = 4.625

Holley Gus’s it’s the answer

8 0

3 years ago

- 7 ( z - 6 ) = - 70

NemiM [27]

Answer:

z=16

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−7(z−6)=−70

(−7)(z)+(−7)(−6)=−70(Distribute)

−7z+42=−70

Step 2: Subtract 42 from both sides.

−7z+42−42=−70−42

−7z=−112

Step 3: Divide both sides by -7.

−7z /−7 = −112 /−7

z=16

7 0

3 years ago

Read 2 more answers

If the graph of f(r)

kondor19780726 [428]

Answer:

yes yes yes yes no yes hcycrztdugguib

7 0

3 years ago

Graph the function and identify the domain and range. y = 0.5x2 A. domain: range: B. domain: range: C. domain: range: D. domain:

vivado [14]

The graph would be a parabola which passes through the origin and opens upwards
The domain is all Real x.

The range is y >= 0

4 0

3 years ago

Model Exponential Growth Question :A sample of bacteria is growing at a continuously compounding rate. The sample triples in 10

Iteru [2.4K]

Answer:

The number of bacteria $B$ after $d$ days is given by

$B = B_0 (3)^{\frac{1}{10} d}$

where $B_0$ is the initial number of bacteria.

Step-by-step explanation:

The number of bacteria $B$ in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is

$B = B_0 *3,$

where $B_0$ is the initial number of bacteria in the sample.

After the 2nd 10th days, the number of bacteria is

$B = (B_0 *3)*3$

after the 3rd day,

$B =( B_0 *3*3)*3$

and so on.

Thus, the formula we get for the number of bacteria after the <em>n</em>th 10-days is

$B = B_0 (3)^n$

where $n$ is is the <em>n</em>th 10-days.

Since, $n$ is 10 days, we have

$d =10n$

$n =\dfrac{1}{10}$

Substituting that into $B = B_0 (3)^n$ , we get:

$\boxed{ B = B_0 (3)^{\frac{1}{10} d}}$

8 0

3 years ago