<u>Question 4</u>
1) bisects , , and (given)
2) (an angle bisector splits an angle into two congruent parts)
3) and are right angles (perpendicular lines form right angles)
4) and are right triangles (a triangle with a right angle is a right triangle)
5) (reflexive property)
6) (HA)
<u>Question 5</u>
1) and are right angles, , is the midpoint of (given)
2) and are right triangles (a triangle with a right angle is a right triangle)
3) (a midpoint splits a segment into two congruent parts)
4) (HA)
5) (CPCTC)
<u>Question 6</u>
1) and are right angles, bisects (given)
2) (reflexive property)
3) (an angle bisector splits an angle into two congruent parts)
5) (HA)
6) (CPCTC)
7) bisects (if a segment splits an angle into two congruent parts, it is an angle bisector)
<u>Question 7</u>
1) and are right angles, (given)
2) and are right triangles (definition of a right triangle)
3) (vertical angles are congruent)
4) (transitive property of congruence)
6) (HA theorem)
7) (CPCTC)
8) bisects (definition of bisector of an angle)
Answer:
0
Step-by-step explanation:
Write out the 2 equations:
2x + y = -3
-2y = 6+4x
-You then pick a variable that you want to solve for. I chose to solve for y because it would be a bit easier.
-2y = 6 + 4x
-Divide both sides by -2 to isolate the variable
(-2y) / -2 = (6 + 4x) / -2
-it comes out to y = -3 -2x
-Now that you have the y you can plug in the value into the second equation.
2x + y = -3 ---> 2x + (-3 -2x) = -3
This can be simplified to:
2x - 3 - 2x = -3
The 2x's cancel out because there is a +2x and a -2x. You are left with a
-3 = -3. If you add 3 to both sides of the equation you end up with 0 = 0, which can be simplified to just 0.
your answer is 12
have a great day! :)
x < -3
2x - 3 < -9
Add 3 to each side
2x - 3+3 < -9+3
2x < -6
Divide by 2
2x/2 < -6/2