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Serggg [28]
3 years ago
14

The square of 9 less than a number is 3 less that the number?

Mathematics
2 answers:
Sladkaya [172]3 years ago
7 0
Nope..........it's not
vlabodo [156]3 years ago
6 0
N - 9^2 = n - 3?
n - 81 ≠ n - 3
There is no possible solution to this statement, so it is a false statement.
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Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
2 years ago
Solve the system <br> 2x+y=-3 <br> -2y=6+4x
ANEK [815]

Answer:

0

Step-by-step explanation:

Write out the 2 equations:

2x + y = -3

-2y = 6+4x

-You then pick a variable that you want to solve for. I chose to solve for y because it would be a bit easier.

-2y = 6 + 4x

-Divide both sides by -2 to isolate the variable

(-2y) / -2 = (6 + 4x) / -2

-it comes out to y = -3 -2x

-Now that you have the y you can plug in the value into the second equation.

2x + y = -3   --->   2x + (-3 -2x) = -3

This can be simplified to:

2x - 3 - 2x = -3

The 2x's cancel out because there is a +2x and a -2x. You are left with a

-3 = -3. If you add 3 to both sides of the equation you end up with 0 = 0, which can be simplified to just 0.

6 0
3 years ago
What is 11.625 rounded to the nearest whole number
Andru [333]

Answer:

your answer is 12

Step-by-step explanation:

have a great day! :)

8 0
3 years ago
Circle the value that solutions of the inequality 2x - 3 &lt; -9
velikii [3]

Answer:

x < -3

Step-by-step explanation:

2x - 3 < -9

Add 3 to each side

2x - 3+3 < -9+3

2x < -6

Divide by 2

2x/2 < -6/2

x < -3

5 0
3 years ago
What is the area of the circle in square units? Select ALL that apply.
lukranit [14]
The answer is F.)
Approximately 50
7 0
3 years ago
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