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3 years ago

HElp ill give 10 points!!!!!!!!!!!!!

Mathematics

1 answer:

Evgesh-ka [11]3 years ago

4 0

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZAnswer:

Step-by-step explanation:

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Keith had 8 1/2 cups of flour. he used 5 2/3 cups to make bread. how many cups of flour does Keith have left

san4es73 [151]

8 1/2 - 5 2/3 =

<span />Hope this helps. :)

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3 years ago

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1. Determine the most precise name for the quadrilateral.

notka56 [123]

rhumbos

it is the most precise name because it gives more information about the quadrilateral

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2 years ago

Solve by completing the square.

rosijanka [135]

7 and 1 i hope u can see

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3 years ago

A linear function contains these points: (0,-1) & (3,8)

Elenna [48]

Answer:

slope: 3

y-intercept: (0, -1)

Find slope:

$\sf slope : \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{\triangle y}{\triangle x} \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points$

Here given points are: (0, -1), (3, 8)

$\rightarrow \sf slope : \dfrac{8-(-1)}{3-0} = \dfrac{9}{3} = 3$

When finding y-intercept, the value of x is 0. Here given y is -1 when x is 0.

y-intercept: -1 or (0, -1)

6 0

2 years ago

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Let f(x)=x^2−2bx, where b is a constant. What can you say about the zeros, y-intercept, axis of symmetry and extreme value of f(

shutvik [7]

Set up equation

${x}^{2} - 2bx$

Factor out an x

$x(x - 2b)$

Set x-2b=0

$x - 2b = 0$

$x = 2b$

So our zeroes are

$0$

$2b$

When we graph our parabola, our y intercept will be at (0,0) and (0,2b).

Our axis of symmetry will be at

${b}$ since we did -b/2a

Our extreme values for this function is a minimum value since our leading factor coefficient (1) is greater than zero.

so plug in b f

into the equation at the very top will give us our minimum.

${b}^{2} - 2b(b)$

${b}^{2} - 2 {b}^{2}$

$- {b}^{2}$

so our miniumum value is

$- {b}^{2}$

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3 years ago

Read 2 more answers