F(x)=x^2+x+5
then
F(3) would be the function evaluated at x=3, or 17.
anytime you see F(3) it is just whatever formula you are looking at evaluated when the variable is equal to 3.
Answer:
9:5
ratios are just putting the numbers next to each other with ':' in the middle
Step-by-step explanation:
Answer:
s = 71 mph, and s+9 = f = 80 mph
Step-by-step explanation:
The distances the two busses travel add up to 604 mi.
Letting f be the faster speed and s the slower. Then f = s + 9 (mph).
Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi. Solve this for s:
4s + 36 + 4s = 604 mi, or 8s = 568. Finally, s = 71 mph, and s+9 = f = 80 mph.
<h3>Option C</h3><h3>The average rate of the reaction over the entire course of the reaction is:

</h3>
<em><u>Solution:</u></em>
Average rate is the ratio of concentration change to the time taken for the change

The concentration of the reactants changes 1.8 M to 0.6 M
here, the time interval given is 0 to 580 sec
Therefore,

Thus option C is correct
Answer:
<em>Terry had £780 initially and Faye had £1300</em>
Step-by-step explanation:
<u>System of Equations</u>
We'll call the following variables:
x = Terry's balance in his bank account
y = Faye's balance in her bank account
The initial relation between them is:

Cross-multiplying:
5x = 3y [1]
If Terry put £220 in his account he had x+220 and if Faye withdrew £300 from her account, she had y-300. Both quantities are equal, thus
x + 220 = y - 300
Subtracting 220:
x = y - 520 [2]
Substituting in [1]
5(y - 520) = 3y
Multiplying:
5y - 2600 = 3y
Adding 2600 and subtracting 3y:
2y = 2600
Dividing by 2:
y = 1300
From [2]:
x = 1300 - 520
x = 780
Terry had £780 initially and Faye had £1300