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Brums [2.3K]
3 years ago
8

HElp ill give 10 points!!!!!!!!!!!!!

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
4 0

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZAnswer:

Step-by-step explanation:

You might be interested in
What does f(3) means ?
Butoxors [25]

F(x)=x^2+x+5  

then  

F(3) would be the function evaluated at x=3, or 17.

anytime you see F(3) it is just whatever formula you are looking at evaluated when the variable is equal to 3.

5 0
3 years ago
Ryan has 9 lollipops and 5 chocolate bars. What is the ratio of lollipops to chocolate bars?
anzhelika [568]

Answer:

9:5

ratios are just putting the numbers next to each other with ':' in the middle

Step-by-step explanation:

4 0
3 years ago
two buses leave towns 604 mi apart at the same time and travel toward eachother. One bus travels 9 mi/h faster than the other on
muminat

Answer:

s = 71 mph, and s+9 = f = 80 mph

Step-by-step explanation:

The distances the two busses travel add up to 604 mi.

Letting f be the faster speed and s the slower.  Then f = s + 9 (mph).

Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi.  Solve this for s:

4s + 36 + 4s = 604 mi, or 8s = 568.  Finally, s = 71 mph, and s+9 = f = 80 mph.


3 0
3 years ago
The table shows the concentration of a reactant in the reaction mixture over a period of time.
saveliy_v [14]
<h3>Option C</h3><h3>The average rate of the reaction over the entire course of the reaction is: 2.0 \times 10^{-3}</h3>

<em><u>Solution:</u></em>

Average rate is the ratio of concentration change to the time taken for the change

Average\ rate = \frac{ \triangle c }{\triangle t }

The concentration of the reactants changes 1.8 M to 0.6 M

here, the time interval given is 0 to 580 sec

Therefore,

Average\ rate = \frac{1.8-0.6}{580} \\\\Average\ rate = \frac{1.2}{580} \\\\Average\ rate \approx 2.0 \times 10^{-3}

Thus option C is correct

5 0
3 years ago
The ratio of money in Terry's bank account to Faye's bank account was 3:5.
inn [45]

Answer:

<em>Terry had £780 initially and Faye had £1300</em>

Step-by-step explanation:

<u>System of Equations</u>

We'll call the following variables:

x = Terry's balance in his bank account

y = Faye's balance in her bank account

The initial relation between them is:

\frac{x}{y}=\frac{3}{5}

Cross-multiplying:

5x = 3y        [1]

If Terry put £220 in his account he had x+220 and if Faye withdrew £300 from her account, she had y-300. Both quantities are equal, thus

x + 220 = y - 300

Subtracting 220:

x = y - 520         [2]

Substituting in [1]

5(y - 520) = 3y

Multiplying:

5y - 2600 = 3y

Adding 2600 and subtracting 3y:

2y = 2600

Dividing by 2:

y = 1300

From [2]:

x = 1300 - 520

x = 780

Terry had £780 initially and Faye had £1300

7 0
2 years ago
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