Question

I need to perform the operation

Answer 1

(-5$x^{2}$ -4x-1)+(-4$x^{2}$-4x)

=-5$x^{2}$ -4x-1-4$x^{2}$-4x

=-9$x^{2}$-8x-1

Answer 2

Answer:

$( - 5x^{2} \times - 4x \: - 1)( - 4^{2} - 4x)$

$(((0 - (5 • ( { \times }^{2} ))) - 4x) - 1) + ((0 - {2}^{2} {x}^{2} ) - 4x)$

$(((0 - 5 {x}^{2} ) - 4x) - 1) + ( - 4 {x}^{2} - 4x)$

Full out like factors:

$- 9 {x}^{2} - 8x - 1 • = - 1(9 {x}^{2} + 8x + 1$

Factoring

$9 {x}^{2} + 8x + 1$

The first term is,  $9 {x}^{2}$ its coefficient is  9 .

The middle term is,  $+ 8x$ its coefficient is  8 .

The last term, "the constant", is $+ 1$

Step-1 : Multiply the coefficient of the first term by the constant   9 • 1 = 9 

Step-2 : Find two factors of  9  whose sum equals the coefficient of the middle term, which is   8 .

$-9x^2 - 8x - 1$