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Eddi Din [679]
3 years ago
13

Mary leaves her house to take a walk. In the graph shows the distance d in feet from her house that Mary is at any given time t

in minutes how many minutes has Mary walk when she reaches the farthest point from her house?
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
5 0
Is that all that asks in the question
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A lifeguard is in a look out chair and sees a person in distress. The eye level of the lifeguard is 15 feet above the ground. Th
faltersainse [42]

Answer:

Horizontal distance between lifeguard and the person is 22 feet.

Step-by-step explanation:

Given: A lifeguard sees a person in distress.The eye level of the lifeguard is 15 feet above the ground. Angle of depression is 34°.

To find: Horizontal distance between lifeguard and the person.

Solution : If we draw a triangle then tan∅ = \frac{height}{base}

               Here base is the horizontal distance.

               Now we put the values in the formula.

               tan 34° = \frac{15}{base}

              Or Base = \frac{15}{tan34}

                             = \frac{15}{0.675} = 22.22 feet

So the answer is 22 feet.

7 0
3 years ago
Help me with this!!!!
sdas [7]

Answer:

IJ = 34

Step-by-step explanation:

Since HK = JK, then IK is a perpendicular bisector and Δ is isosceles, then

IJ = HI , that is

2s = s + 17 ( subtract s from both sides )

s = 17

Then

IJ = 2s = 2 × 17 = 34

7 0
3 years ago
Read 2 more answers
Last week at the park Haeather ran 4 miles in 48 minutes when she runs her next race she Hope's to improve her time by 2 minutes
Korvikt [17]

Answer:

Haeather ran at a speed of 5 miles per hour.

Step-by-step explanation:

Given that last week at the park Haeather ran 4 miles in 48 minutes, to determine what was Haeather rate of speed in miles per hour the following mathematical calculation must be performed:

48/4 = 12

Thus, Haeather ran 1 mile every 12 minutes.

60/12 = 5

1 x 5 = 5

Therefore, Haeather ran at a speed of 5 miles per hour.

3 0
3 years ago
In the triangle EFG,
MariettaO [177]

Answer:

4.\ \sin E = \cos G

Step-by-step explanation:

Given

\triangle EFG

\angle F = 90^o --- right angle

Required

Which of the options is true

In a triangle, we have:

\angle E + \angle F + \angle G = 180^o --- angles in a triangle

Substitute \angle F = 90^o

\angle E + 90^o + \angle G = 180^o

Collect like terms

\angle E + \angle G = 180^o -90^o

\angle E + \angle G =90^o

This implies that E and G are complementary angles.

For complementary angles, E and G;

\sin E = \cos G and \sin G = \cos E

<em>Hence, (4) is true</em>

7 0
3 years ago
ANSWER SUPER FAST!! Eric practiced the violin and guitar for 8 hours this week. He practiced the piano for 1/4 of that time. How
EleoNora [17]

Answer:

2 hours

Step-by-step explanation:

one fourth of 8 hours is 2 hours. Divide 8 by 4

5 0
3 years ago
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