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Goryan [66]
3 years ago
5

What is 77x99 need this help plz

Mathematics
2 answers:
Elan Coil [88]3 years ago
7 0
77*99=7623 is the answer. :)
Maksim231197 [3]3 years ago
6 0
77x99=7623 Used a calculator
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Estimate the answer to 28.56 – 15.98 by first rounding each number to the nearest whole number. A. 13 B. 12.7 C. 12 D. 10
Scorpion4ik [409]
The answer is 12.58 rounded up it would be 13 so the correct answer is A
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a owner increases the rent office house by 5% at end of each year if current its rent is ₹2500pm how much will be the rent after
sergeinik [125]

Answer:

2950$

Step-by-step explanation:

2500×5%=125$

125×2=250$

2500+250=3960$

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Linda takes out a loan for $4,000 she will repay the loan in 4 years Linda will pay $560 in interest how much is Linda's loan pa
Schach [20]

Answer:

$1,280 every year and $106.66 every month.

Step-by-step explanation:

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3 years ago
Find the HCF of 1045 and 1520 by long division. Method​ plsss
aliina [53]

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95

Step-by-step explanation:

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3 years ago
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with a mean of 1262 chips
Sholpan [36]

Answer:

Using z score formula:

X = z ∂ + µ

 = 157.833

Step-by-step explanation:

Solution:

Mean = µ = 1262

Standard deviation = ∂ = 117

(a) 28th percentile for the number of chocolate chip.

P( z < z) = 28%

             = 0.28

P( z<- 0.58)  = 0.28

Z = -0.58

By using z score formula:

Z = x - µ /∂

-0.58= x – 117 / 1262

X = (- 0.58)(117) + (1262)

 =  1194.14

(b) Middle 97% of bag.

P(-z < z < z) = 97%

                    = 0.97

P( z < z) – p(z < -z) = 0.97

2p(z < z) -1 = 0.97

2p (z < z) = 1 + 0.97

P(z < z) = 1.97 / 2

            = 0.99

P(z < 2.33) = 0.99

Z ± 2.33

By using z score formula:

Z = x - µ / ∂

X = z ∂ + µ

  = - 2.33 x 117 + 1262

  =989.39

Z = 2.33

X = z ∂ + µ

  =  2.33 x 117 + 1262

 =1533.61

(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate.

By using standard normal table,

The z dist’n formula:

P(z < z ) = 25%

            =0.25

P(z < -0.6745) = 0.25

Z = 0.6745

Using z score formula:

X = z∂ + µ

   = - 0.6745 x 117 + 1262

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First quartile = Q1 =1183.0835

The third quartile is:

P(z<z) = 75%

    = 0.75

P(z < 0.6745) = 0.75

Z = 0.6745

Using z score formula:

X = z ∂ + µ

  = 0.6745 x 117 + 1262

= 1340.9165

IQR = Q3 – Q1

     = 1340.9165 – 1183.0835

  = 157.833

3 0
3 years ago
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