Answer:
(a) There are asymptotes at x=3/2 and x=-1/3
Step-by-step explanation:
The denominator zeros can be found by factoring:
f(x) = (x +1)/((2x -3)(3x +1))
Neither of the denominator factors is cancelled by the numerator factor, so each represents a vertical asyptote, not a function hole.
The asymptotes are at the values of x where the denominator is zero:
2x -3 = 0 ⇒ x = 3/2
3x +1 = 0 ⇒ x = -1/3
Answer:
Equation in square form:
Extreme value:
Step-by-step explanation:
We are given
we can complete square
we can use formula
now, we can add and subtract 5^2
So, we get equation as
Extreme values:
we know that this parabola
and vertex of parabola always at extreme values
so, we can compare it with
where
vertex=(h,k)
now, we can compare and find h and k
we get
h=-5
k=-4
so, extreme value of this equation is
