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Juliette [100K]
3 years ago
14

13 x - 7 / 10 x ^ 2 - 11 x + 3​

Mathematics
2 answers:
xenn [34]3 years ago
5 0

Answer:

\frac{1}{10} x (20x-7x^{2} + 30)

Step-by-step explanation:

2x-\frac{7}{10} x^{2} +3

Mars2501 [29]3 years ago
4 0

Answer:

\frac{1}{10} (20x - 7x^2+30)

Step-by-step explanation:

13x-\frac{7}{10} x^2 -11x + 3

Combine liked terms

(13x-11x) -\frac{7}{10} x^2  + 3

2x - \frac{7}{10} x^{2} + 3

\frac{1}{10} (20x - 7x^2+30)

Hope that helps!

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alukav5142 [94]

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4 years ago
A metallurgist has an alloy with 5
alexira [117]
\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.30y\\
-----&-----&-------&-------\\
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\end{array}

so hmm notice, we use the decimal format for the percent, namely 15% is just 15/100 and 5% is just 5/100 and so on

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and whatever the concentrated amounts are, they'll add up to (100)(0.15)

thus     \bf \begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.30y=(100)(0.15)\\
----------\\
0.05x+0.30\left( \boxed{100-x} \right)=(100)(0.15)
\end{cases}

solve for "x", to see how much 5% alloy will be needed

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4 0
4 years ago
I need help on this question can someone help x(x-2)
Anestetic [448]
X * (x-2) = x*x - 2*x = x^{2} - 2x
6 0
3 years ago
Read 2 more answers
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