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Oksana_A [137]
2 years ago
9

Solve for x, given the equation Square root of x-5+7=11

Mathematics
1 answer:
denis-greek [22]2 years ago
6 0

\sqrt{x-5+7} = 11\\x-5+7 = 11^2\\x-5+7 = 121\\x + 2 = 121\\x = 119

Check the answer:

\sqrt{119-5+7} \\\sqrt{114+7} \\\sqrt{121} \\11

This answer is correct,

x = 119

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David and Rob each got the same-size pack of crackers. David
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Answer: Rob ate more crackers.

Symbol answer: 6/12 < 9/12

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Common knowledge: Anytime you have the same numerator, with a different denominator, the one with the bigger denominator is always smaller. For example, if had a pizza with 6 slices and a pizza with 4 slices, the one with 6 slices and smaller and the one with 4 slices and bigger. Even though 6>4 that mindset has to change when thinking about a problem like this.

<em>Another explanation: </em>

<em>If you still don’t get it, simply find a common denominator, so we’ll choose 12. Take 3/6 and multiply that by 2/2 so you get 6/12 and then take 3/4 and multiply that by 3/3 on both the (numerator and denominator) and that equals 9/12.</em>

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7 0
2 years ago
Solve:
STatiana [176]

The solutions to the equation 3-k=\sqrt{3k+1} are k = 1 and 8

The given equation is:

3-k=\sqrt{3k+1}

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Expand the left side of the equation above

(3-k)^2=3k+1\\\\(3-k)(3-k)=3k+1\\\\3^2-3k-3k+k^2=3k+1\\\\9-6k+k^2=3k+1

Write the quadratic equation in standard form

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Factor the quadratic equation

(k-8)(k-1)=0

Use the zero product property

k - 8 = 0

k = 8

k - 1 = 0

k = 1

The solutions to the equation 3-k=\sqrt{3k+1} are k = 1 and 8

Learn more here: brainly.com/question/25840704

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