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Oksana_A [137]
3 years ago
9

Solve for x, given the equation Square root of x-5+7=11

Mathematics
1 answer:
denis-greek [22]3 years ago
6 0

\sqrt{x-5+7} = 11\\x-5+7 = 11^2\\x-5+7 = 121\\x + 2 = 121\\x = 119

Check the answer:

\sqrt{119-5+7} \\\sqrt{114+7} \\\sqrt{121} \\11

This answer is correct,

x = 119

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PLSSS HURRY ILL GIVE YOU A BRAINLYEST
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Answer:

36 inches

Step-by-step explanation:

lets think of it as a ratio,

80:w

20:9

so we want 20 to get to 80

and 9 to get to w right?

so if we just move the smaller rectangle to the corner, then 20*4=80 right?

and if we do that, we do it to 9 as well, 9*4=36

w=36

6 0
2 years ago
Can some one help me w my math
KiRa [710]

Answer: It would be B

Step-by-step explanation:

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7 0
3 years ago
What is the answer to this decimal problem 0.32÷n=0.032
11111nata11111 [884]

10 because you know that the decimal moves one to the left if you are dividing by ten and one to the right if you are multiplying by ten.

Check your work. 0.32 divided by 10 is 0.032

6 0
2 years ago
Read 2 more answers
What is fraction equivalent to 4/4? explain how you know
Helen [10]

Answer:

1, 2/2, 3/3, 5/5, etc.

Step-by-step explanation:

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I hoped this is what you wanted.

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8 0
3 years ago
Please solve these questions for me. i am having a difficult time understanding.
s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

1)

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

\angle AED = \angel BEC ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

2)

Refer the attached figure

\angle ABC = 90^{\circ}

In ΔDBC

BC=DC (Given)

So,\angle CDB=\angle DBC(Opposite angles of equal sides are equal)

So,\angle CDB=\angle DBC=x

So,\angle CDB+\angle DBC+\angle BCD = 180^{\circ} (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So,\angle CDB=\angle DBC=x = 65^{\circ}

Now,

\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90

So,\angle ABD=90-x=90-65=25^{\circ}

In ΔABD

AB = BD (Given)

So,\angle BAD=\angle BDA(Opposite angles of equal sides are equal)

So,\angle BAD=\angle BDA=y

So,\angle BAD+\angle BDA+\angle ABD = 180^{\circ}(Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0
3 years ago
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