(HELP ME I CANT) Find the length of sides of ∆OTP if O is the centre of the circle ,PT is the length of
1 answer:
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Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
The area of the given rectangle is 51
Step-by-step explanation:
First we have to find the coordinates of the vertices of the rectangle.
Then the length and breadth of it using distance formula.
The distance d between points (x₁ , y₁) and (x₂ , y₂) is given by
Finally calculate the area of rectangle using the formula,
Area of rectangle = Length * Breadth
From the given graph, we get the coordinates of the rectangle as
A(2,4) , B(-2,3) , C(1,-9) , D(5,-8)
Breadth, AB =
Length, BC =
Now, Area of rectangle = Length * Breadth = AB * BC = √17 * 3√17 = 3 *17 = 51
∴ The area of the given rectangle is 51