The quotient: 1
the remainder: 48
Given:
First term of an arithmetic sequence is 2.
Sum of first 15 terms = 292.5
To find:
The common difference.
Solution:
We have,
First term: 
Sum of first 15 terms: 
The formula of sum of first n terms of an AP is
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Where, a is first term and d is common difference.
Putting
, n=15 and a=2 in the above formula, we get
![292.5=\dfrac{15}{2}[2(2)+(15-1)d]](https://tex.z-dn.net/?f=292.5%3D%5Cdfrac%7B15%7D%7B2%7D%5B2%282%29%2B%2815-1%29d%5D)
![292.5=\dfrac{15}{2}[4+14d]](https://tex.z-dn.net/?f=292.5%3D%5Cdfrac%7B15%7D%7B2%7D%5B4%2B14d%5D)
![292.5=15[2+7d]](https://tex.z-dn.net/?f=292.5%3D15%5B2%2B7d%5D)
Divide both sides by 15.




Dividing both sides by 7, we get


Therefore, the common difference is 2.5.
It is 4170 I believe if my calculations are correct
6÷40.5= $6.75 per hour
8÷54= $6.75 per hour
y= 6.75x
Answer:
m<2 = 4x - 26 = 4(30) - 26 = 94 degrees
m<3 = 3x + 4 = 3(30) + 4 = 94 degrees
Step-by-step explanation:
Congruent angles are equal, so m<2 = m<3
4x - 26 = 3x + 4
x = 30
m<2 = 4x - 26 = 4(30) - 26 = 94 degrees
m<3 = 3x + 4 = 3(30) + 4 = 94 degrees