If employment is expected to increase by 14.8% between 01/2009 and 01/2016 and the employees number 19, 100 in 01/2009, how many
1 answer:
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Answer:
21,500
Step-by-step explanation:
Given data ( in thousand ) in this year,
28 31 34 35 37 41 42 42 42 47 49 51 52 52 60 61 67 72 75 77,
If each data is increased by $ 3000 in the next year,
So, the data for the next year,
31 34 37 38 40 44 45 45 45 50 52 54 55 55 63 64 70 75 78 80,
Since, the data is already arranged in the ascending order,
The median is 51 which is between 50 and 52,
Thus, the lower half of the Data is, 31 34 37 38 40 44 45 45 45 50,
Having median =
= 42,
Upper half of the data is 52 54 55 55 63 64 70 75 78 80,
Having median = 63.5
Hence, the interquartile range =
= 63.5 - 42
= 21.5
That is, the Interquartile range would be 21, 500.
Answer:
See explanation
Step-by-step explanation:
Let a,b, and c be real numbers.
The distributive property says that:
Assuming we want to simplify:
We apply the distributive property to get:
We can now use rules of exponents to simplify further: