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lianna [129]
2 years ago
9

15.5 × [(2 × 2.4) + 3.2] – 24

Mathematics
1 answer:
scZoUnD [109]2 years ago
6 0

Answer:100

Step-by-step explanation:

2 x 2.4=4.8

4.8+3.2=8.0

15.5 x 8.0=124.00

124.00-24=

100

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Solve simultaneously <br>2 log y=log 2 + log x <br>2 to power y = 4 to power x<br>​
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Answer:

Step-by-step explanation:

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3 years ago
For women at hartford college, times to run 400 meters are normally distributed with a mean of 84 seconds and a standard deviati
pashok25 [27]


z=(63-84)/3= -21/7= -3
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4 0
3 years ago
What is the sign of a.
posledela

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3 years ago
Subtract 6 from me. Then multiply by 2. If you subtract 40 and then divide by 4, you get 8. What number am I?
aliina [53]

Answer:

42

Step-by-step explanation:

Let the number be "x"

We translate the word equation to algebraic equation.

First,

subtract 6 from me, so we have:

x - 6

Now,

Multiply by 2, so we have:

2(x-6)

Now,

Subtract 40, then divide by 4:

\frac{2(x-6)-40}{4}

Now, you get "8", so equate this to 8, we get:

\frac{2(x-6)-40}{4}=8

We now solve using algebra:

\frac{2(x-6)-40}{4}=8\\2(x-6)-40=4*8\\2(x-6)-40=32\\2x-12-40=32\\2x-52=32\\2x=32+52\\2x=84\\x=42

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7 0
3 years ago
On a particular production line,the likelihood that a light bulb is defective is 5%. Ten light bulbs are randomly selected. What
KengaRu [80]

Answer:

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

Step-by-step explanation:

Consider the provided information,

Let X is the number of defective bulbs.

Ten light bulbs are randomly selected.

The likelihood that a light bulb is defective is 5%.

Therefore sample size is = n = 10

Probability of a defective bulb = p = 0.05.

Therefore, q = 1 - p = 1 - 0.05 = 0.95

Mean of binomial random variable: \mu=np

Therefore, \mu=10(0.05)=0.5

Variance of binomial random variable: \sigma^2=npq

Therefore, \sigma^2=10(0.05)(0.95)=0.475

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

5 0
3 years ago
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