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3 years ago

I need help find how much tension is in the string????

Physics

1 answer:

Nikitich [7]3 years ago

5 0

Answer:

When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.

Image result for I need help find how much tension is in the string???? And can you explain how you got it after you get the answer plz????

Hence, in such a case the tension will be equal to the centrifugal force.

Formula for tension = centrifugal force = mv2/r.

So the formula of tension will be = centripetal force – force of gravity = mv2/r – mg = m(v2/r-g)

The formula of tension will be = centripetal force + force of gravity = mv2/r + mg = m(v2/r+g)

Explanation:

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A uniform 1.5 T magnetic field points north. If an electron moves perpendicular (90 degrees) with a speed of 2.5x10 ^7 m/s, thro

Dmitry_Shevchenko [17]

Answer:

i think its 470

Explanation:

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3 years ago

On Earth, the number flux of solar neutrinos from the p-p chain is:

Nataly [62]

Answer:

Explanation:

The volume of the tank = 50 kton

50 kton = 5 × 10⁷ kg

Since 18 grams of water will contain: 10 electrons × 6.023 × 10²³

Then;

5× 10⁷ kg will contain $( \dfrac{5 \times 10^7 \times 10^3}{18}) \times 10 \times 6.023 \times 10^{23}$

= 1.67 × 10³⁴ electrons

(b)

Suppose:

$f_{neutrino} = \dfrac{2f_o}{26.2 MeV} = 6.7\times 10^{10} \ s^{-1} cm^{-2}$

Then;

10⁻⁶ of $f_{neutrino} = 6.7 \times 10^{10} \times 10^{-6} \ s^{-1} cm^{-2}$

$=6.7 \times 10^{4}\ s^{-1} cm^{-2}$

Thus, the number of high energy neutrinos which will interact with water is:

= $6.7 \times 10^4 \times \sigma$

= $6.7 \times 10^4 \times 10^{-43}$

= $6.7 \times 10^{-39} s^{-1}$

For 1.67 × 10³⁴ electrons, the detection rate is:

$6.7 \times 10^{-39} \times 1.67 \times 10^{34}$

$= 11.19 \times 10^{-5} \ s^{-1}$

= 9.668 per day

3 0

3 years ago

If an object is dropped from a tall building and it hits the ground 3.0 s later, what is the velocity of the object when it hits

ikadub [295]

Answer:

-29.4 m/s

Explanation:

Initial velocity is 0 m/s.

Acceleration is -9.8 m/s².

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v = at + v₀

v = (-9.8)(3.0) + 0

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7 0

3 years ago

Read 2 more answers

Which is greater 10 newtons or 5 pounds

Tpy6a [65]

On Earth, 1 kilogram of mass weighs 9.8 newtons or 2.2 pounds.

9.8 newtons = 2.2 pounds

(9.8/2.2) newtons = 1 pound = 4.45 newtons

   (2.2/9.8) pounds = 1 newton = 0.225 pound

5 pounds = (5 x 4.45 newtons) = 22.2 newtons.

    22.2 newtons is more than 10 newtons, so
   5 pounds is more than 10 newtons.

6 0

3 years ago

The magnetic moment of the Earth is approximately 8.00 ×10²²A.m² . Imagine that the planetary magnetic field were caused by the

Serhud [2]

$4.315 \times10^{45}$ unpaired electrons,are required each with a magnetic moment of 9.27 ×10⁻²⁴A.m² , to participate .

Magnetic moment, also called magnetic dipole moment, is a measure of the tendency of an object to align with a magnetic field.
Magnetic moment is a vector quantity. Objects tend to be placed so that their magnetic moment vectors are parallel to the lines of magnetic force.
The direction of the magnetic moment points from the south pole of the magnet to the north pole. The magnetic field produced by a magnet is directly proportional to its magnetic moment.

"Magnetic moment is defined as the magnetic strength and orientation of a magnet or other object that produces a magnetic field."

It is given that magnetic moment of the Earth is approximately 8.00 ×10²²A.m² .

Number of unpaired is found by dividing the magnetic moment of the Earth to the given magnetic moment of 9.27 ×10⁻²⁴A.m²

$n=\frac{8.00\times10^{22}}{9.27\times10^{-24}} \\\\n=8.63\times10^{45}$

Each iron atom has two unpaired electrons, so the number of iron atoms required is $\frac{1}{2}\times 8.63\times10^{45}=4.315\times10^{45}$ electrons.

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