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Shtirlitz [24]
3 years ago
15

I need help find how much tension is in the string????

Physics
1 answer:
Nikitich [7]3 years ago
5 0

Answer:

When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.

Image result for I need help find how much tension is in the string???? And can you explain how you got it after you get the answer plz????

Hence, in such a case the tension will be equal to the centrifugal force.

Formula for tension = centrifugal force = mv2/r.

So the formula of tension will be = centripetal force – force of gravity = mv2/r – mg = m(v2/r-g)

The formula of tension will be = centripetal force + force of gravity = mv2/r + mg = m(v2/r+g)

Explanation:

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dimaraw [331]

Answer:

The magnets need to be placed with red closest to blue.

Opposite poles attract.

The magnets will be attracted to each other with enough force to stick together.

Explanation:

6 0
3 years ago
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4 years ago
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Suppose I produce radio waves with an antenna that have a peak electric field amplitude E and peak magnetic field amplitude B. I
denis23 [38]

Answer:

Correct answer is 2B

Explanation:

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E=cB

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3 0
3 years ago
1. *A car is going over the top of a hill whose curvature approximates a circle of radius 200 m. At
Greeley [361]

Answer:

The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s

Explanation:

The given parameters are;

The curvature of the hill, r = 200 m

Due to the velocity, v, the occupants weight = 20% less than the normal weight

The outward force of an object due to centripetal (motion) force is given by the following equation;

F_c = \dfrac{m \times v^2}{r}

Where;

r = The radius of curvature of the hill = 200 m

Given that the weight of the occupants, W = m × g, we have;

F_c = 0.2 \times W = 0.2 \times m \times g

\therefore 0.2 \times m \times g = \dfrac{m \times v^2}{r}

v = √(0.2 × g × r)

By substitution, we have;

v = √(0.2 × 9.81 × 200) ≈ 19.81

The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.

3 0
3 years ago
What happens to the velocity of an object when balanced force acts on it?
Pani-rosa [81]
When the entire group of forces acting on an object is balanced,
the individual forces all add up to zero, and the effect on the object
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No force on it means no acceleration ... no change in speed or
direction of motion.

No change in speed or direction of motion means constant velocity.
8 0
4 years ago
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