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jonny [76]
3 years ago
11

How we will solve this question? 36.45cL=______=μL

Physics
1 answer:
QveST [7]3 years ago
8 0

Answer:

0.364

I believe... Good luck!

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Marks: 1
____ [38]

Answer:

W = 5W

Explanation:

1W = 1J/s

W = Watts

J = Joules

s = seconds

W = J/s

W = 300J/60s

W = 5W

6 0
2 years ago
What evidence would you observe if the law of conservation of mass is obeyed when mixing two solutions?​
Marianna [84]

Answer:

You should have noticed that the number of atoms in the reactants is the same as the number of atoms in the product. The number of atoms is conserved during the reaction. However, you will also see that the number of molecules in the reactants and products are not the same.

3 0
2 years ago
The figure shows five electric charges. Four charges with the magnitude of the charge 2.0 nC form a square with the size a = 4.0
bearhunter [10]

Considering the four electric charges forming a square with magnitude of charge of 2.0 nC on each. :

A) Magnitude of the force on the 5.5 nC charge in the middle of the figure = 3.48 * 10^-4 N

B) Direction of the force on the 5.5 nC charge in the middle of the figure = Leftward ( negative x -axis )

Using the given data :

size of square = 4 cm

magnitudes of four charges = 2.0 nC

<u> a) </u><u>magnitude</u><u> of the force on the center charge </u>

Electric force between two point charges = F = \frac{1}{4\pi *E_{o} } \frac{q1q2}{r^2} ----- ( 1 )

where ; \frac{1}{4\pi E_{o} } = 9 * 10^9 Nm^2/C^2

step 1 ; find r ( distance between charges )

r² = ( 2 )² + ( 2 )² = 8 cm²  

back to equation 1

F = 9 * 10⁹ * \frac{2 * 10^{-9} *  (5.5 * 10^{-9})  }{8*10^{-4} } =  1.23 * 10^-4  N

∴ magnitude of the force on the center charge ( Fnet )= 4F cos 45°

        = 4 * ( 1.23 * 10^-4 ) * \frac{1}{\sqrt{2} }  = 3.48 * 10^-4 N

b) The direction of the force at the center is along the negative x-axis ( leftward )

Learn more : brainly.com/question/24139734

6 0
2 years ago
A liquid retains a fixed volume regardless of the shape of the container which holds it. truefalse
VashaNatasha [74]
The answer is True hope it helps
3 0
2 years ago
Read 2 more answers
A particle that has a charge of 7.4 μC moves with a velocity of magnitude 3 × 105 m/s along the +x axis. It experiences no magne
sweet [91]

Answer:

Explanation:

F = qvB

Where F equal to the magnetic force on the particle.

q = charge on the particle

v = velocity of the particle

B =Magnetic field

F = 0.520N

q = 7.4 μC = 7.4×10-⁶C

v = 3×10⁵m/s

B= ?

B = F/qv

B = 0.520/(7.4×10-⁶ ×3×10⁵)

B = 0.234T.

6 0
3 years ago
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