Question

An ideal incompressible fluid flows at 12 m/s in a horizontal pipe. If the pipe widens to twice its original radius, what is the flow speed in the wider section?
a) 4 m/sb) 6 m/sc) 12 m/sd) 3 m/s

Answer 1

Answer:

d) 3 m/s

Explanation:

As we know by equation of continuity

$A_1v_1 = A_2v_2$

here we have

$A_1 = \pi r^2$

$A_2 = \pi (2r)^2$

$A_2 = 4\pi r^2$

now from above equation we have

$\pi r^2 v_1 = 4\pi r^2 v_2$

$v_2 = \frac{v_1}{4}$

here we have

$v_1 = 12 m/s$

$v_2 = 3 m/s$