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11Alexandr11 [23.1K]
3 years ago
14

An ideal incompressible fluid flows at 12 m/s in a horizontal pipe. If the pipe widens to twice its original radius, what is the

flow speed in the wider section?
a) 4 m/sb) 6 m/sc) 12 m/sd) 3 m/s
Physics
1 answer:
grandymaker [24]3 years ago
5 0

Answer:

d) 3 m/s

Explanation:

As we know by equation of continuity

A_1v_1 = A_2v_2

here we have

A_1 = \pi r^2

A_2 = \pi (2r)^2

A_2 = 4\pi r^2

now from above equation we have

\pi r^2 v_1 = 4\pi r^2 v_2

v_2 = \frac{v_1}{4}

here we have

v_1 = 12 m/s

v_2 = 3 m/s

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