1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
astraxan [27]
3 years ago
10

Car B has the same mass as Car A but is going twice as fast. If the same constant force brings both cars to a stop, how far will

car B travel in coming to rest as compared to the distance car A traveled
Physics
1 answer:
evablogger [386]3 years ago
7 0

Answer:four times

Explanation:

Given

mass of both cars A and B are same suppose m

but velocity of car B is same as of car A

Suppose velocity of car A is u

Velocity of car B is 2 u

A constant force is applied on both the cars such that they come to rest by travelling certain distance

using  to find the distance traveled

where, v=final velocity

u=initial velocity

a=acceleration(offered by force)

s=displacement

final velocity is zero

For car A

0-(u)^2=2\times a\times s

s_a=\frac{u^2}{2a}------1

For car B

0-(2u)^2=2\times a\times s_b

s_b=\frac{4u^2}{2a}----2

divide 1 and 2 we get

\frac{s_a}{s_b}=\frac{1}{4}

thus s_b=4\cdot s_a

distance traveled by car B is four time of car A

You might be interested in
A point charge of -3.0 x 10-5C is placed at the origin of coordinates. Find the electric field at the point 3. r= 50 m on the x-
Snezhnost [94]

Answer: -5×10-3

Explanation:

E=kq/r

4 0
2 years ago
What effect does time have on the speed of a moving object
sergejj [24]
Velocity is d/t distance over time. Increase velocity (speed) decrease. Increase d velocity increases.
6 0
3 years ago
Flying against the wind, a jet travels 4640 in 8 hours. flying with the wind, the same jet travels 9000 in 9 hours. what is the
Vanyuwa [196]
17 in wind and 13640 meh buddy
3 0
3 years ago
The total resistance of a 15-ohm, an 65-ohm and a 35-ohm resistor connected in parallel ​
yanalaym [24]

Answer:

I think its 9.0397 Ohms

Explanation:

take the reciprocal of all the resistances: 1/15, 1/65, 1/35

then add them: = 151/1365

then reciprocal the answer: =1365/151

And chuck it on a calculator: =9.04 Ohms

I think this is right but I'm not entirely sure. Tell me if I'm right by the way!

3 0
3 years ago
At a given instant the bottom A of the ladder has an acceleration aA = 4 f t/s2 and velocity vA = 6 f t/s, both acting to the le
Nana76 [90]

Answer:

Acceleration=24.9ft^2/s^2

Angular acceleration=1.47rads/s

Explanation:

Note before the ladder is inclined at 30° to the horizontal with a length of 16ft

Hence angular velocity = 6/8=0.75rad/s

acceleration Ab=Aa +(Ab/a)+(Ab/a)t

4+0.75^2*16+a*16

0=0.75^2*16cos30°-a*16sin30°---1

Ab=0+0.75^2sin30°+a*16cos30°----2

Solving equation 1

(0.75^2*16cos30/16sin30)=angular acceleration=a=1.47rad/s

Also from equation 2

Ab=0.75^2*16sin30+1.47*16cos30=24.9ft^2/s^2

6 0
3 years ago
Other questions:
  • In a scale model solar system that used a grapefruit to represent the Sun, how far away should you put another grapefruit to rep
    14·1 answer
  • A crowbar makes our work easier by multiplying effort true or false​
    10·1 answer
  • Find the x-components of this vector: 92.5 m, 32.0 degrees. Remember, angles are measured from the +x axis.
    7·1 answer
  • Good coding specialists share which of the following characteristics?
    12·2 answers
  • "The team wants to delete from Dataset A all activities related to users in Dataset B. How can an Einstein Consultant help them
    12·1 answer
  • Michael has a substance that he puts in Container 1. The substance has a volume of 5 cubic meters. He then puts the substance in
    13·1 answer
  • A student watches a video about forces.
    6·1 answer
  • Pleaseee help as soon as possible!!
    15·1 answer
  • Guys helppppp pleaseeeeeeeee
    5·1 answer
  • URGENT <br> Find the total<br> equivalent<br> resistance for the<br> circuit.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!