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astraxan [27]
3 years ago
10

Car B has the same mass as Car A but is going twice as fast. If the same constant force brings both cars to a stop, how far will

car B travel in coming to rest as compared to the distance car A traveled
Physics
1 answer:
evablogger [386]3 years ago
7 0

Answer:four times

Explanation:

Given

mass of both cars A and B are same suppose m

but velocity of car B is same as of car A

Suppose velocity of car A is u

Velocity of car B is 2 u

A constant force is applied on both the cars such that they come to rest by travelling certain distance

using  to find the distance traveled

where, v=final velocity

u=initial velocity

a=acceleration(offered by force)

s=displacement

final velocity is zero

For car A

0-(u)^2=2\times a\times s

s_a=\frac{u^2}{2a}------1

For car B

0-(2u)^2=2\times a\times s_b

s_b=\frac{4u^2}{2a}----2

divide 1 and 2 we get

\frac{s_a}{s_b}=\frac{1}{4}

thus s_b=4\cdot s_a

distance traveled by car B is four time of car A

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Answer:

103239.89 days

Explanation:

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                                    \frac{(43.07)^{3}}{T^{2}}  =  7.496 * 10^{-6}  

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