FREE BRAINLIEST

Reil [10]

Answer: So if Allison has 30 beads and each bracelet has 7. She would make 4 bracelets with 2 left over. The sentence would be If Alyson made 4 bracelets she would use 28 beads, leaving 2 left over.

Step-by-step explanation: 30/7 is 4 with a remainder of 2

4 0

3 years ago

PLZZZZZZzzzzzZzZzZzZzZZz BRAINLIESTTTTTTTT

Cloud [144]

Answer:

A) 3, B) 8 and 4, C) 12

Step-by-step explanation:

There are 3 terms: 8x^2, 4x, and 12.

The coefficiemts are numbers that come before a variable. That's why the coefficients are 8 and 4.

The constant is the number that doesn't come with a variable, thus 12.

5 0

2 years ago

Read 2 more answers

On Monday, 365 students went on a

Tamiku [17]

45 on each bus. 365 minus 5 in cars is 360. Divided by 8 to get 45.

6 0

2 years ago

Read 2 more answers

Solving a right triangle (ROUND TO THE NEAREST TENTH)

Kay [80]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for B

B = 180° - (90 + 40)° = 180° - 130° = 150°

--------------------------------------------------------------

sin40° = $\frac{opposite}{hypotenuse}$ = $\frac{a}{21}$

Multiply both sides by 21

21 × sin40° = a, thus

a ≈ 13.5 ( to the nearest tenth )

--------------------------------------------------------------

cos40° = $\frac{adjacent}{hypotenuse}$ = $\frac{b}{21}$

Multiply both sides by 21

21 × cos40° = b, thus

b ≈ 16.1 ( to the nearest tenth )

3 0

3 years ago

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 340 babies were born, a

Bas_tet [7]

Answer:

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

b)Yes, the proportion of girls is significantly different from 0.5.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

In the study 340 babies were born, and 289 of them were girls. This means that $n = 340, \pi = \frac{289}{340} = 0.85$

Use the sample data to construct a 99% confidence interval estimate of the percentage of girls born.

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 - 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.80$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 + 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.90$

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

Does the method appear to be effective?

b)Yes, the proportion of girls is significantly different from 0.5.

4 0

3 years ago