A concentric-tube heat exchanger cools hot water owing at 1 kg/s from 80C to 30C. It uses air owing at 5 kg/s to perform this co
oling operation. Air enters at 10C and exits at 51.5C. (a) What is the log-mean-temperature-di erence
2 answers:
Answer:
The log-mean-temperature-difference is 24.03⁰C
Step-by-step explanation:
First we need to know if the heat exchanger is in parallel flow or counter-flow. However, counter flow arrangement is best used to recover heat.
L.M.T.D for counter flow is given as;
where;
Thf₁ is the initial temperature of the hot fluid = 80°C
Tcf₂ is the final temperature of the cold fluid = 51.5°C
Thf₁ - Tcf₂ = 80 - 51.5 = 28.5⁰C
Thf₂ is the final temperature of the hot fluid = 30°C
Tcf₁ is the initial temperature of the cold fluid = 10°C
Thf₂ - Tcf₁ = 30 - 10 = 20⁰C
Therefore, the log-mean-temperature-difference is 24.03⁰C
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Answer:
If the number of blue tiles in the bag is 180, then the probability of randomly drawing a red tile equal to 1/10.
Step-by-step explanation:
Total number of red tiles in a bag = 20
Let us assume the number of blue tiles in a bag = p
So, the total number of tiles in a bag = Red Tiles + Blue tiles
= 20 + p
Now, let us find the probability of drawing a red tile:
But, here the probability of drawing a red tile = 1/10
or, p = 180
Hence, if the number of blue tiles in the bag = 180, then the P Picking out a red tile ) is 1/10.