21v + 8 - 12v - 7 + 3t - 1t = (combine like terms)
9v + 2t + 1 <==
25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer: 6.403 miles; or, write as: 6.403 mi. .
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Explanation:
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5
--------------------------------------------
` right angle |_ |
` (right triangle ) |
` | 4
` |
`
"c" ` \
(hypotenuse) Starting point
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Since we have a "right triangle, we solve for "c"; using the
"Pythagorean theorem" ;
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→ a² + b² = c² ; Solve for "c" ; our answer (in "miles"; or, "mi.") ;
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Given : a = 4; b = 5 ;
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Plug these known values into our equation:
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→ 4² + 5² = c² ;
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→ 16 + 25 = c² ; ↔ c² = 16 + 25 ;
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→ c² = 41 ;
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→ Take the positive square root of each side of the equation (since the side of a "triangle" cannot be "negative";
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→ √(c²) = √(41) ;
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→ c = √41 ; Use calculator;
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→ c = 6.40312423743 ; Round to:
→ c = 6.403 miles; or, 6.403 mi.
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1.666666666666667%
3.00/1.80
1.666666666666667 as a fraction is 5/3
10x10x10 which is 1000 have a great day
