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kiruha [24]
2 years ago
15

Match equivalent expressions. Numbers and letters go together

Mathematics
1 answer:
dedylja [7]2 years ago
3 0

Answer:

(a) (x+9) (x+2)

(b)(x-2) (x-3)

(c) (x+2) (x+3)

(f) (x-9) (x-2)

(2) x2+11x+18

(3) x2-7x - 18

(6) x2+5x+6

Step-by-step explanation:

You might be interested in
What is addition of 2/3 + 1/4​
Anuta_ua [19.1K]
Answer: 2/3 + 1/4 = 11/12

The least common denominator of both denominators is 12.


The first fraction , 3 x 4 = 12

2 2x4 8
— = —— = —
3 3x4 12

The second is the same , 4 x 3 = 12
1 1x3 3
— = —— = —
4 4x3 12

Add both fractions:

8 3 8 + 3 11
— + — = ——— = —
12 12 12 12

3 0
3 years ago
Why is this hard. I'm not a genius. but genius can only solve this problem.
miss Akunina [59]

Answer:

4 + 4 = 8

+    +

8 - 4 = 6

||    ||

13  8

___________________________

i dont iknow if im right :(

6 0
2 years ago
Read 2 more answers
What are the first 3 composite numbers that are multiples of 4 and greater than 10.
insens350 [35]

Answer:

12, 16, and 20

Step-by-step explanation:

These are the answers because:

1) Composite numbers mean numbers that are divisible by more than two numbers (1 and itself).

2) Multiples of 4 that are greater than 10 are: 12, 16, and 20 because they are all divisible by more than two numbers, they are greater than 10, and they are mutiples of 4. You can check if they are multiples of 4 by skip counting or multiplying: 4, 8, 12, 16, 20 or 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16, 4 x 5 = 20.

Therefore, the answers are: 12, 16, and 20

Hope this helps! :D

7 0
3 years ago
Read 2 more answers
Let X denote the number of flaws along a 100-m reel of magnetic tape (an integer-valued variable). Suppose Zdenote the number of
Lemur [1.5K]

Answer:

a) P(20 \leq X \leq 30) = P(20-0.5 \leq X \leq 30+0.5)

P(19.5 \leq X \leq 30.5) = P(\frac{19.5-25}{5} \leq Z \leq \frac{30.5 -25}{5})=P(-1.1 \leq Z \leq 1.1)

And we can find this probability like this:

P(-1.1 \leq Z \leq 1.1)= P(Z\leq 1.1) -P(Z\leq -1.1) = 0.864-0.136= 0.728

b) P(X \leq 30)= P(X

And using the z score we got:

P(X

c) P(X

And if we use the continuity correction we got:

P(X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Continuity correction means that we need to add and subtract 0.5 before standardizing the value specified.

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(25,5)  

Where \mu=25 and \sigma=5

Part a

For this case we want to find this probability:

P(20 \leq X \leq 30) = P(20-0.5 \leq X \leq 30+0.5)

And if we use the z score given by:

z =\frac{x-\mu}{\sigma}

We got this:

P(19.5 \leq X \leq 30.5) = P(\frac{19.5-25}{5} \leq Z \leq \frac{30.5 -25}{5})=P(-1.1 \leq Z \leq 1.1)

And we can find this probability like this:

P(-1.1 \leq Z \leq 1.1)= P(Z\leq 1.1) -P(Z\leq -1.1) = 0.864-0.136= 0.728

Part b

For this case we want this probability:

P(X \leq 30)

And if we use the continuity correction we got:

P(X \leq 30)= P(X

And using the z score we got:

P(X

Part c

For this case we want this probability:

P(X

And if we use the continuity correction we got:

P(X

3 0
3 years ago
suppose you are in your last semester of college and have a 2.75 GPA after 105 credit hours if you are taking 15 credit hours in
Valentin [98]

Answer:

The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.

Step-by-step explanation:

Given,

CGPA = 2.75

Credit hours = 105

Last semester GPA = 4

Last semester credit hours = 15

CGPA = \frac{sum of (Credit hours of each subject * GPA of each subject)}{Total credit hours}credit hours * gpa

in our case, it would be:

CGPA = \frac{(2.75*105)+(4*15}{105+15}

=> \frac{(288.75)+(60)}{120}

=> \frac{348.75}{120}

=> 2.90

The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.

7 0
3 years ago
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