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Olin [163]
3 years ago
12

Your history teachers is going to give you a 92 point assessment. There are 2 point questions and 3 point questions. If there is

a total of 40 questions on the assessment, how many questions are worth 2 points?
Mathematics
2 answers:
Sedaia [141]3 years ago
6 0

Answer: 28

Step-by-step explanation:

Let x be the number of 2 mark questions

Let y be the number of 3 mark questions

x+y=40. ---------------(1)

2x+3y=92 ---------------(2)

Solve equation (1) for y

y=40−x

Substitute

y=40−x in equation (2)

2x+3(40−x)=92

2x+120−3x=92

2x−3x=92−120

−x=−28

x=28

Substitute

x=28 in equation (1)

28+y=40

y=40−28=12

Number of 2 mark questions

=28

Number of 3 mark questions

=12

Temka [501]3 years ago
4 0

Answer:

28

Step-by-step explanation:

x = 2 point questions, y = 3 point questions

x + y = 40

2x + 3y = 92

Solving this we get x = 28, y = 12 so the answer is 28.

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A school cotains 357 boys and 323 girls if a student is chosen at random, what is the probability that it is a girl
solong [7]

Answer:

P(G)=0.475

Step-by-step explanation:

From the question we are told that:

Number of boysN_b=357

Number of girls N_g=323

Total Number of students

N_t=N_b+N_g

N_t=680

Generally the equation for Probability of Choosing a Girl is mathematically given by

P(G)=\frac{N_g}{N_t}

P(G)=\frac{323}{680}

P(G)=0.475

3 0
3 years ago
A force of 12 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i
sattari [20]

Answer:

Work done in stretching the spring = 7.56 lb-ft.

Step-by-step explanation:

Normal length of the spring = 8 in or \frac{8}{12} ft

= \frac{2}{3} ft

If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in

= \frac{11}{12} ft

Force applied to stretch the spring = 12 lb

By Hook's law,

F = kx [where k is the spring constant and x = length by which the spring is stretched]

12 = k(\frac{2}{3})

k = 18

Work done (W) to stretch the spring by \frac{11}{12} ft will be

W = \int\limits^\frac{11}{12} _0 {kx} \, dx

    = \int\limits^\frac{11}{12} _0 {(18x)} \, dx

    = 18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0

    = 9(\frac{11}{12})²

    = 7.56 lb-ft

6 0
3 years ago
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just olya [345]

Answer:

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Step-by-step explanation:

because 20-10 is 10

8 0
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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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