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sergij07 [2.7K]
3 years ago
6

How many solutions does this equation have?

Mathematics
1 answer:
Marianna [84]3 years ago
5 0
6x 34 because you have to divide and then multi
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3s(4 + 6)2 is an example of
lyudmila [28]

Answer:

A. An Algebraic Expression

Step-by-step explanation:

Since we have no equal sign in the problem, we know that it is an expression. An equation has an equal sign and another value so we can simplify to find the value of whatever variable we are working with. We also know that it is not anything numerical because we are working with variables. With this information we will see that the correct answer is A.

Best of Luck!

8 0
2 years ago
Read 2 more answers
What is 5+6f =11 hhhhhhhhhhyhy
zepelin [54]

Hello!

Answer:

\boxed{f=1}

The answer should have positive sign.

Step-by-step explanation:

First, you subtract by 5 from both sides of an equation.

5+6f-5=11-5

Then, simplify and subtract by the numbers from left to right.

11-5=6

6f=6

You divide by 6 from both sides of an equation.

\frac{6f}{6}=\frac{6}{6}

Finally, divide numbers from left to right.

6\div 6=1

\boxed{f=1}, which is our correct answer.

Hope this helps you!

Have a nice day! :)

-Charlie

Thank you so much!

5 0
3 years ago
Read 2 more answers
Find the percent of the discount when the original price is 79.75 andbthe sales price is 14.85
Neporo4naja [7]
Steps:
1. Do 79.75 minus 14.85 which is 64.9
2. 64.9 is how much the discount was
3. You do a proportion
X/100 times 64.9/79.75
4. 64.9 times 100= 6,490
5. 6,490 divided by 79.75 is 81.379
Your answer is
81.379%
6 0
3 years ago
Identify the values of a, b, and c in the following quadratic equation. 6x 2 + x - 6 = 0
Maurinko [17]

Answer:

a = 6 \\ b = 1 \\ c  =  - 6

Step-by-step explanation:

6x^{2}  + x - 6 = 0 \\  equating \: it \: with \\ a {x}^{2}  + bx + c = 0 \\ a = 6 \\ b = 1 \\ c  =  - 6

8 0
3 years ago
Х = 6y + 3<br> x+2y = 5<br><br> What’s the first step?
katovenus [111]

Answer:

subtract 2y

Step-by-step explanation:

x= 5-2y or x= -2y+5

7 0
3 years ago
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