Question

Father gave each of his children one-twelfth of a cake. Then he ate the remaining one-third of the cake. How many children does Father have?

Answer 1

Answer:

the father has 8 children

Step-by-step explanation:

The cake = 1 whole = 12/12 = 3/3

If the father ate 1/3 of the cake, we know that 2/3 of the cake was divided amongst his children

How many 1/12's can fit into 2/3?

• (2/3) / (1/12) --> (2/3) x (12/1) = (24/3) = 8

If 8 1/12-pieces can fit into 2/3 of a cake, the father has 8 children.

Answer 2

$\bold{\huge{\red{\underline{ Solution 1 }}}}$

Given :-

• Father have each of his children 1/12th of a cake
• He ate the remaining 1/3rd of the cake.

To Find :-

• We have to find the number of children father have?

Let's Begin :-

Let the total children be x

According to the question,

Children ate 1/12th portion of the cake that is

One child will got

$\sf{=}{\sf{\dfrac{ x}{12}}}$

The remaining 1/3 of the cake had eaten by father

So,

Total portion of cake = 1

Therefore,

$\sf{\dfrac{x}{12}}{\sf{ + }}{\sf{\dfrac{ 1}{3}}}{\sf{ = 1}}$

$\sf{\dfrac{ x + 4}{12 }}{\sf{ = 1 }}$

$\sf{ x + 4 = 1 × 12 }$

$\sf{ x + 4 = 12}$

$\sf{ x = 12 - 4 }$

$\sf{ x = 8 }$

Hence, The total children does father have is 8 .

$\bold{\huge{\red{\underline{ Solution 2 }}}}$

Given :-

• Lisa watch is 15 minute slow
• Mike's watch is 25 minute fast
• The present time showing by Lisa watch is 9:43

To Find :-

• We have to find the present time shown by mike's watch.

Let's Begin :-

Let the present time be x

According to the question,

• Lisa watch is 15 minutes slow and present time shown by Lisa watch is 9:43

Therefore,

$\sf{ x - 0:15 = 9 : 43 }$

$\sf{ x = 9 : 43 + 0:15 }$

$\sf{ x = 9 : 43 + 0:15 }$

$\sf{ x = 9 : 58 }$

Hence, The present time is 9:58

Now,

• Mike watch is 25 minutes fast

Therefore,

Present time shown by mike's watch

$\sf{ = x + 0:25 }$

$\sf{ = 9:58 + 0:25 }$

$\sf{ = 10:23}$

Hence, The present time shown by mike's watch is 10:23