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Mice21 [21]
3 years ago
7

A tarantula was walking along the sidewalk and walked 30 centimeters in 5 seconds. What was the average speed of the spider?

Chemistry
1 answer:
Marina CMI [18]3 years ago
7 0
I’m pretty sure you would have to divide 5 and 30 and you will get 0.16666666 but I would think it would be 6cm/s but I could be wrong and if it is I’m am truly sorry.
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the molar mass is the mass of a given chemical element or chemical compound divided by the amount of substance

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Which gas laws apply to each of the steps of the 4 stroke engine?
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The ideal gas law ... A gas turbine, which uses continuous combustion, simply exhausts its ... This makes them ideal for use in vehicles, as they also start up more ... A four stroke engine delivers one power stroke for every two cycles of ... ignition, exhaust) however, these steps occur 3 times per one spin of. Internal combustion engine.

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Consider the equation below. CaCO3(s) <—>CaO(s) + CO2(g) what is the equilibrium constant expression for the given reactio
hichkok12 [17]

Answer:

Answer is: Keq = [CO₂].

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Pure liquids (shown in chemical reactions by appending (l) to the chemical formula) and solids (shown in chemical equations by appending (s) to the chemical formula) not go in to he equilibrium constant expression, only gas state (shown in chemical reactions by appending (g) to the chemical formula) reactants and products go in to  the equilibrium constant expression

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A cylindrical container of garlic powder has a height of 9 cm and 1.2 times the radius of another cylindrical container of the s
andreev551 [17]
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5 0
3 years ago
Octane has a density of 0.692 g/ml at 20oc. how many grams of o2 are required to burn 15.0 gal of c8h18 (the average capacity of
Hatshy [7]

Octane has a density of 0.692 g/ml at 20°C. Grams of O₂ required to burn 15.0 gal of C₈H₁₈ is 1.37868×10⁵g.

Octane is a hydrocarbon having eight carbon atoms and have single bonds only.

Given,

Density of octane = 0.692g/ml

Temperature = 20°C = 293K

Amount of Octane present = 15gal

Molar mass of octane = 114g

We know that,

1 gal = 3.78541L = 3785.4ml

Hence, 15 gal = 56781 ml

Now let's calculate the Mass of octane required:

Mass of octane = 0.692 x 56781

Mass of octane = 39292.45 g

According to the given equation,

C₈H₁₈ + 12.5O₂ ---------> 8CO₂ + 9H₂O

Also, 114g of octane needs-------> 400g of oxygen

39292.45g of octane needs ---------> 137868.24g of oxygen

Hence, oxygen needed to burn octane is 1.37868×10⁵g

Learn more about Octane here, brainly.com/question/21268869

#SPJ4

4 0
2 years ago
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