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lidiya [134]
3 years ago
9

A car travels at 15 kilometers west in 10 minutes after reaching the destination the car travels back to the starting point agai

n taking 5 minutes what is the average velocity of the car
Chemistry
1 answer:
blsea [12.9K]3 years ago
3 0
The distance there and back is 30 kilometers. The total time is 15 minutes. Divide the distance by the time to get 2 kilometers. The average velocity is 2 kilometers. Hope this helps! ;)
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Base your answer on the information below. The hydrocarbon 2-methylpropane reacts with iodine as represented by the balanced equ
Kryger [21]

Answer:

See explanation

Explanation:

The boiling point of a substance is affected by the nature of bonding in the molecule as well as the nature of intermolecular forces between molecules of the substance.

2-methylpropane has only pure covalent and nonpolar C-C and C-H bonds. As a result of this, the molecule is nonpolar and the only intermolecular forces present are weak dispersion forces. Therefore, 2-methylpropane has a very low boiling point.

As for 2-iodo-2-methylpropane, there is a polar C-I bond. This now implies that the intermolecular forces present are both dispersion forces and dipole interaction. As a result of the presence of stronger dipole interaction between 2-iodo-2-methylpropane molecules, the compound has a higher boiling point than  2-methylpropane.

3 0
3 years ago
Why does green light slow down more than orange light does ​
patriot [66]

Answer:

Green light has longer wavelengths than orange light. Green light has fewer particles than orange light. Green light refracts less than orange light. That is why Green light slows down more quickly than orange light does.

6 0
3 years ago
A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products h
statuscvo [17]

Explanation:

First, calculate the moles of CO_{2} using ideal gas equation as follows.

                PV = nRT

or,          n = \frac{PV}{RT}

                = \frac{1 atm \times 4.41 ml}{0.0821 Latm/mol K \times 293 K}      (as 1 bar = 1 atm (approx))

                = 0.183 mol

As,   Density = \frac{mass}{volume}

Hence, mass of water will be as follows.

                Density = \frac{mass}{volume}

             0.998 g/ml = \frac{mass}{3.26 ml}    

                 mass = 3.25 g

Similarly, calculate the moles of water as follows.

        No. of moles = \frac{mass}{\text{molar mass}}

                              =  \frac{3.25 g}{18.02 g/mol}            

                              = 0.180 mol

Moles of hydrogen = 0.180 \times 2 = 0.36 mol

Now, mass of carbon will be as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

          0.183 mol =  \frac{mass}{12 g/mol}            

                              = 2.19 g

Therefore, mass of oxygen will be as follows.

              Mass of O = mass of sample - (mass of C + mass of H)

                                = 3.50 g - (2.19 g + 0.36 g)

                                = 0.95 g

Therefore, moles of oxygen will be as follows.

          No. of moles = \frac{mass}{\text{molar mass}}

                               =  \frac{0.95 g}{16 g/mol}            

                              = 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

                         C              H           O

No. of moles:  0.183        0.36       0.059

On dividing:      3.1           6.1            1

Therefore, empirical formula of the given compound is C_{3}H_{6}O.

Thus, we can conclude that empirical formula of the given compound is C_{3}H_{6}O.            

6 0
3 years ago
Which of these compounds are molecular?<br> CBr4<br> FeS<br> P4O6<br> PbF2
olasank [31]

Answer:

I think it's answer is P4O6

I hope it's helpful for you...

8 0
3 years ago
A box is sitting on a table. The upward force exerted on the box that stops it from falling through the table is known as the __
romanna [79]

It is know as the normal force.


When a solid is placed on a support, the latter exerts forces on the solid at each point of contact. These are forces that oppose the weight and prevent an object from falling.

This force is usually vertical and upward and often offsets the weight. If the solid is in equilibrium on the support the forces compensate the weight of the solid.

6 0
3 years ago
Read 2 more answers
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