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3 years ago

How would you prepare a saturated solution of potassium nitrate?

1 answer:

5 0

Using titration method,

Pipette 25 cm3 of KOH into a conical flask. Add a few drops of methyl orange(indicator).
Then pour a beaker of Dilute nitric acid (HNO3) into a burette. Record the readings of the burette before starting.

1)While releasing some nitric acid into the conical flask, swirl the conical flask.
2)Stop swirlimg or adding nitric acid when color of the solution in the conical flask turns light pink. That will be end point. Record the reading of the burette.
3)Repeat the experiment without adding methyl orange(indicator)
4)Add the same vol of nitric acid used previously.
5)Solution in conical flask transfer over to a dish.
6)Heat the solution till it becomes saturated.

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Nitrogen and oxygen do not react appreciably at room temperature, as illustrated by our atmosphere. But at high temperatures, th

Gre4nikov [31]

Answer : The equilibrium concentration of NO is, 0.0092 M.

Solution :

First we have to calculate the concentration of NO.

$\text{Concentration of NO}=\frac{\text{Moles of }NO}{\text{Volume of solution}}=\frac{0.3152mol}{2.0L}=0.1576M$

The given equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

Initially conc. 0 0 0.1576

At eqm. (x) (x) (0.1576-2x)

The expression of $K_c$ will be,

$K_c=\frac{[NO]^2}{[N_2][O_2]}$

$0.0153=\frac{(0.1576-2x)^2}{(x)\times (x)}$

By solving the term, we get:

$x=0.0742,0.0839$

Neglecting the 0.0839 value of x because it can not be more than initial value.

Thus, the value of 'x' will be, 0.0742 M

Now we have to calculate the equilibrium concentration of NO.

Equilibrium concentration of NO = (0.1576-2x) = [0.1576-2(0.0742)] = 0.0092 M

Therefore, the equilibrium concentration of NO is, 0.0092 M.

5 0

3 years ago

draw the organic product formed when 1−hexyne is treated with h2o, h2so4, and hgso4. click the draw structure button to launch t

V125BC [204]

The organic product formed when 1−hexyne is treated with H₂O, H₂SO₄, and HgSO₄ will be 2-hexanone (structure attached).

This reaction is an example of an oxymercuration reaction of the organic product 1−hexyne.

Oxymercuration is shown in three steps to the right. The nucleophilic double bond attacks the mercury ion, releasing an acetoxy group. The mercury ion's electron pair attacks carbon on the double bond, generating a positive-charged mercuronium ion. Mercury's dxz and 6s orbitals give electrons to the double bond's lowest unoccupied molecular orbitals.

In the second stage, the nucleophilic H₂O attacks the highly modified carbon, freeing its mercury-bonding electrons. Electrons neutralize mercury ions by collapsing. Water molecules have positive-charged oxygen.

In the third stage, the negatively charged acetoxy ion released in the first step attacks the hydrogen of the water group, generating the waste product HOAc. The two electrons in the oxygen-hydrogen link collapse into oxygen, neutralizing its charge and forming alcohol.

You can also learn about organic products from the following question:

brainly.com/question/13513481

#SPJ4

4 0

1 year ago

Give six examples of complex compounds.

ra1l [238]

Answer:

Examples of complex compound include potassium ferrocyanide K4[Fe(CN)6] and potassium ferricyanide K3[Fe(CN)6]. Other examples include pentaamine chloro cobalt(III) chloride [Co(NH)5Cl]Cl2 and dichlorobis platinum(IV) nitrate [Pt(en)2Cl2](NO3)2.

3 0

3 years ago

Which one of the following statements is FALSE? a In a neutralization reaction, an acid reacts with base to produce a salt and H

pishuonlain [190]

Answer: Option (c) is the correct answer.

Explanation:

HF is a weak acid and not a strong acid. This is because fluorine is a highly electronegative atom and when it combines with a hydrogen atom then it will attract the valence electron of hydrogen atom more towards itself.

As a result, it will not dissociates easily to give hydrogen ion. Hence, it acts as a weak acid.

A neutralization reaction is defined as a reaction in which an acid reacts with a base to give salt and water. For example, $HCl + NaOH \rightarrow NaCl + H_{2}O$

It is true that, spectator ions "appear in the total ionic equation for a reaction, but not in the net ionic equation".

Titration is defined as a process in which concentration of an unknown solution is determined using a solution of known concentration.

Thus, we can conclude that the statement HF, HCl, and HNO3 are all examples of strong acids, is false.

7 0

2 years ago

When heating a chemical solution over an open flame in a test tube you should - A. keep a cork in the test tube so the solution

Alla [95]

Hello.

The answer is: A. keep a cork in the test tube so the solution cannot spill out

B and C both could be very deadly and it shouldnt be D because if u have an open flame you shouldnt open it even if its not towards anyone.

have a nice day

3 0

2 years ago