Answer:
2.82 L
T₁ = 303 K
T₂ = 263 K
The final volume is smaller.
Explanation:
Step 1: Given data
- Initial temperature (T₁): 30 °C
- Initial volume (V₁): 3.25 L
- Final temperature (T₂): -10 °C
Step 2: Convert the temperatures to Kelvin
We will use the following expression.
K = °C + 273.15
T₁: K = 30°C + 273.15 = 303 K
T₂: K = -10°C + 273.15 = 263 K
Step 3: Calculate the final volume of the balloon
Assuming constant pressure and ideal behavior, we can calculate the final volume using Charles' law. Since the temperature is smaller, the volume must be smaller as well.
V₁/T₁ = V₂/T₂
V₂ = V₁ × T₂/T₁
V₂ = 3.25 L × 263 K/303 K = 2.82 L
Answer: C) Heat
What I know so far is that heat makes it harder for the electrons to reach the source, thus making it hard to collide with the nucleus, but I’m not sure so you can see if it’s correct.
Answer:
Concentration of original solution = 1.66
Explanation:
We know that

We have given concentration of NaOH = 0.1678
Volume of NaOH = 19.88 mL = 0.01988 L
So moles of NaOH = volume x concentration of NaOH
= 
Moles of
in 10 mL of diluted solution = 1/2 x moles of NaOH
=
x 0.00333 = 0.00166 mol
Moles of
in 25 mL of original solution
= moles of H2SO4 in 250 mL of diluted solution
=
x 0.00166 = 0.0415 mol
Concentration of original solution = 
= 
Answer:
The metals have the tedency to lose electrons and become positive ions
Explanation:
In order to attain noble gases electronic configuration, metals of group I A lose one electron and II A lose 2 electrons with ionization energy.