Answer:
The correct answer is option B.
Explanation:

Moles of
= 40 mol
Moles of NaOH = 48 mol
According to reaction, 3 moles of NaOH reacts with 2 moles 
Then ,48 moles of NaOH will reacts with:
of 
Then ,40 moles of
will reacts with:
of NaOH
As we can see that 48 moles of sodium will completey react with 32 moles of nitrogen tribromide.
Moles left after reaction = 40 mol - 32 mol = 8 mol
Hence, the
is an excessive reagent.
Answer:
87.3 calories of heat is required.
Explanation:
Heat = mcΔT
m= mass, c = specific heat of silver, T = temperature
H= 57.8 g * 0.057 cal/g°C * ( 43.5 - 17 °C)
H = 57.8 * 0.057 * 26.5
H = 87.3069 cal.
The heat required to raise the temperature of 57.8 g of silver from 17 °C to 43.5 °C is 87.3 calories.
Answer and Explanation:
We need to remember the formulas:
- pOH = -log[OH-]
- pH = -log[H+]
- pH + pOH = 14
When given the concentration of OH-, denoted as [OH-], we can plug that value into the equation pOH = -log[OH-] to find the pOH. Once we have found the pOH, we can then subtract that value from 14 to determine the value of pH.