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Deffense [45]
3 years ago
9

How would you prepare a saturated solution of potassium nitrate?

Chemistry
1 answer:
ValentinkaMS [17]3 years ago
5 0
Using titration method,

Pipette 25 cm3 of KOH into a conical flask. Add a few drops of methyl orange(indicator).
Then pour a beaker of Dilute nitric acid (HNO3) into a burette. Record the readings of the burette before starting.

1)While releasing some nitric acid into the conical flask, swirl the conical flask.
2)Stop swirlimg or adding nitric acid when color of the solution in the conical flask turns light pink. That will be end point. Record the reading of the burette.
3)Repeat the experiment without adding methyl orange(indicator)
4)Add the same vol of nitric acid used previously.
5)Solution in conical flask transfer over to a dish.
6)Heat the solution till it becomes saturated.
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zimovet [89]

Answer:

ph is the amount of toxins right

4 0
4 years ago
6. A balloon filled with air has a volume of 3.25 L at 30°C. It is placed in a freezer at
Viefleur [7K]

Answer:

2.82 L

T₁ = 303 K

T₂ = 263 K

The final volume is smaller.

Explanation:

Step 1: Given data

  • Initial temperature (T₁): 30 °C
  • Initial volume (V₁): 3.25 L
  • Final temperature (T₂): -10 °C
  • Final volume (V₂): ?

Step 2: Convert the temperatures to Kelvin

We will use the following expression.

K = °C + 273.15

T₁: K = 30°C + 273.15 = 303 K

T₂: K = -10°C + 273.15 = 263 K

Step 3: Calculate the final volume of the balloon

Assuming constant pressure and ideal behavior, we can calculate the final volume using Charles' law. Since the temperature is smaller, the volume must be smaller as well.

V₁/T₁ = V₂/T₂

V₂ = V₁ × T₂/T₁

V₂ = 3.25 L × 263 K/303 K = 2.82 L

7 0
3 years ago
I will give 20 points for correct answer. No links!
NikAS [45]
Answer: C) Heat

What I know so far is that heat makes it harder for the electrons to reach the source, thus making it hard to collide with the nucleus, but I’m not sure so you can see if it’s correct.
5 0
3 years ago
A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solutio
Alja [10]

Answer:

Concentration of original solution = 1.66

Explanation:

We know that

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

We have given concentration of NaOH = 0.1678

Volume of NaOH = 19.88 mL = 0.01988 L

So moles of NaOH = volume x concentration of NaOH

= 0.01988\times 0.1678=0.00333mole

Moles of H_2SO_4 in 10 mL of diluted solution = 1/2 x moles of NaOH

= \frac{1}{2} x 0.00333 = 0.00166 mol

Moles of H_2SO_4 in 25 mL of original solution

= moles of H2SO4 in 250 mL of diluted solution

= \frac{250}{10} x 0.00166 = 0.0415 mol

Concentration of original solution = \frac{moles}{volume}

= \frac{0.0415}{0.025}=1.66

8 0
3 years ago
Do metals or nonmetals have the greatest tendency to lose electrons and become positive ions?
vekshin1

Answer:

The metals have the tedency to lose electrons and become positive ions

Explanation:

In order to attain noble gases electronic configuration, metals of group I A lose one electron and II A lose 2 electrons with ionization energy.

8 0
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