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svetlana [45]
2 years ago
9

This is a balanced equation for the combustion of acetylene (c2h2). How many moles of oxygen(o2) are required to react completel

y with 1. 0 mole of acetylene?.
SAT
1 answer:
alexgriva [62]2 years ago
7 0

Considering the reaction stoichiometry, 2.5 moles of O₂ are required to react completely with 1 mole of acetylene C₂H₂.

<h3>Reaction stoichiometry</h3>

The balanced reaction is:

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • C₂H₂: 2 moles
  • O₂: 5 moles
  • CO₂: 4 moles
  • H₂O: 2 moles

<h3>Moles of oxygen O₂ required</h3>

Then you can apply the following rule of three: if by stoichiometry of the reaction 2 moles of C₂H₂ react with 5 moles of O₂, 1 mole of C₂H₂ reacts with how many moles of O₂?

amount of moles of O_{2} =\frac{1 mole of C_{2} H_{2} x 5 moles of O_{2} }{2 mole sof C_{2} H_{2}}

<u><em>amount of moles of O₂= 2.5 moles</em></u>

Finally, 2.5 moles of O₂ are required to react completely with 1 mole of acetylene C₂H₂.

Learn more about reaction stoichiometry:

brainly.com/question/9536480?referrer=searchResults

brainly.com/question/11564309?referrer=searchResults

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Assuming complete dissociation of the solute, how many grams of kno3 must be added to 275 ml of water to produce a solution that
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The mass of KNO₃ that is required to be added to 275 ml of water is; 108.3 g

<h3>Dissolution of a Solute</h3>

We are given;

K f =  1.86 °C.kg/m

Mass of solution = 275 g = 0.275 Kg

Freezing point of solution = −14.5 °C

Freezing point of pure water = 0.0 °C

We know that;

Δ T = Freezing point of solve nt - Freezing point of solut ion

Thus;

Δ T =  0°C - ( -14.5 °C)

Δ T = 14.5 °C

Also;

Δ T = K f * m * i

where;

K f is free zing con stant

m is m o l a l i t y

i is V a n t H o f f factor

Since KNO₃ produces two particles then; i = 2

Making the m the subject of the formula gives;

m = ΔT /(K × i)

m =  14.5 °C/(1.86 °C . kg/m o l × 2)

m = 3.898 m

Now;

M o l a l i t y = number of mo les/mass of solution in kilograms

Thus;

number of mo les of solute = m o l a l i t y × mass of solution in kilograms

number of mo les of solute= 3.898 m × 0.275 Kg

number of mo les of solute= 1.072 moles

Thus;

Number of mo les = mass/mo lar mass

M o lar mass of KNO₃ = 101 g/mol

Mass = Number of mo les ×  101 g/mol

Mass = 1.072 moles ×  101 g/mol

Mass of KNO₃ = 108.3 g

Read more about dissolution of a solute at; brainly.com/question/1945924

6 0
2 years ago
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