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3 years ago

Find the slope: (-7, 4), (13, 4) O 20 O Zero O Undefined

Mathematics

2 answers:

jenyasd209 [6]3 years ago

5 0

The answer is zero

4-4=0
13-(-7)=20
And since there is no number above the 20 it is zero

NeX [460]3 years ago

4 0

Answer:

Zero

Step-by-step explanation:

it is to correct answer because I did this before and one of my classes also subscribe to my channel bye

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A(1)=20

Paladinen [302]

Answer:

-14

Step-by-step explanation:

You've got a(1)=20

a(1) means a(n) when n=1

the sequence is telling you to take the previous value of a(n), which is a(n-1) and subtract 17

then:

a(2) = a(1)-17 = 20 - 17 = 3

a(3) = a(2) - 17 = 3-17 = -14

3 0

3 years ago

(5x^2-4X + 7) - (4x + 2)

DanielleElmas [232]

5x’2-4x+7-4x-2
We add the two 4
5x’2-8x+7-2
5x’2-8x+5
The answer is
5x’2 -8x +5

3 0

3 years ago

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

case a) $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

case b) $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

case c) $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

case d) $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

the answer is

$x^{2}-2x-4=0$

5 0

3 years ago

Read 2 more answers

PZZZ help!!!!! 25 points!

Cerrena [4.2K]

Answer:

Y=1.25x+3.50

Step-by-step explanation:

The problem is linear so it uses y=ax+b form. In this we can set the left group as x and the right group as y. Then use

(y2-y1) / (x2-x1) to find the slope. once the slope is found (1.25) we can find the y intercept by using one of our coordinates with our equation y-ax=b

12.25-1.25*7=b

b=3.5

now we put them all together to make

Y=1.25x+3.50

7 0

3 years ago

Martha bought new fish for her home aquarium. She Bought 3 guppies and 2 platies for a total of 13.95.Find the price of a guppy

Crazy boy [7]

Bought the same number of Guppies and only Hank bought 2 additional Platies. Thus, let’s subtract the total of Hank and Martha
=> 18.33 – 13. 95 = 4.38
Thus, Hank paid an additional of 4.34 for 2 platies. Let’s divide to get the price of platies
=> 4.34 / 2 = = 2.19 (price of platies each.)
Let’s solve for price of guppies
=> 13.95 – 4.34 = 9.61
=> 9.61 / 3 = 3.20 (Price of guppies each.)

8 0

3 years ago