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2 years ago

1 point

Mathematics

1 answer:

spayn [35]2 years ago

5 0

well, what we do is, simply get the area of the containing rectangle, is an 8x10, and then get the area of the circle, with a radius of half of 4.3 or r = 2.15, and then if we subtract the area of the circle from the rectangle's, what's leftover is the shaded part.

$\stackrel{\textit{\large Areas}}{\stackrel{rectangle's}{(8\cdot 10)}~~-~~\stackrel{circle's}{[\pi (2.15)^2]}}\implies 80-4.6225\pi ~~\approx~~65.5$

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Please help ASAP! I will mark Brainliest! Please answer CORRECTLY! No guessing! CHECK ALL THAT APPLY

Mashutka [201]

Answer:

0,8,5

Step-by-step explanation:

x+22 <32

Subtract 22 from each side

x+22-22 <32-22

x <10

The choices that fit

0,8,5

8 0

2 years ago

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Write an equation in slope-intercept form that goes through (12, 4) and (20,8).

spayn [35]

Answer:

Equation in slope-intercept form that goes through (12, 4) and (20,8) is: $y = \frac{1}{2}x-2$

Step-by-step explanation:

Given two points are:

$(x_1,y_1) = (12,4)\\(x_2,y_2) = (20,8)$

Slope intercept form of line is given as:

$y = mx+b$

Here m is the slope of the line and b is the y-intercept.

Slope of a line is calculated by the formula:

$m = \frac{y_2-y_1}{x_2-x_1}$

Putting the values

$m = \frac{8-4}{20-12}\\m = \frac{4}{8}\\m=\frac{1}{2}$

Putting the value of slope in slope-intercept form we get

$y = \frac{1}{2}x+b$

To find the value of b, any one point will be put in the equation

Putting the first point (12,4) in the equation

$4 = \frac{1}{2}(12) + b\\4 = 6+b\\b = 4-6\\b = -2$

Putting the value of b

$y = \frac{1}{2}x-2$

Hence,

Equation in slope-intercept form that goes through (12, 4) and (20,8) is: $y = \frac{1}{2}x-2$

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2 years ago

Select two ratios that are equivalent to 2:12 A.6:40 B.12:2 C.3:24 D.1:6 E.8:48

Sever21 [200]

Answer:

Step-by-step explanation:

2:12 is equivalent to 8:48

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2 years ago

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complet. each statement by rounding the number to given place value. use the number line to show your work a 53,000 rounded to t

tresset_1 [31]

50,000 because when the number next to the main number is below 5 then you round down...if it is 5 or above then you round up

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3 years ago

Let FS R be a finite set. (a) Prove that F is closed (b) Prove that every point in F is an isolated point.

Lorico [155]

Answer:

a) Suppose that F is ordered in ascending order: $F = \{x_1,\ldots, x_n\}$ . Then, the complement of F can be written as

$F^c = (-\infty,x_1)\cup (x_1,x_2)\cup (x_2,x_3)\cup \cdots \cup (x_{n-1}, x_{n})\cup (x_n,+\infty)$

which is the union of a finite number of open intervals, then $F^c$ is an open set. Thus, F is a closed subset of the real numbers.

b) Take an arbitrary element of F, let us say $x_k$ . Now, choose a real number $\epsilon$ such that

$0$ there are not other element of F, because $\epsilon$ is less that the minimum distance between $x_k$ and its neighbors.

In case that $k=1$ we only consider $0$ , and if $k=n$ we only consider $0$ .

Then, all points of F are isolated.

Step-by-step explanation:

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2 years ago