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Lubov Fominskaja [6]
3 years ago
12

Dave can complete a sales route by himself in 4 hours. James can do the same job in 5 hours. How long will it take them to do it

working together?
Mathematics
1 answer:
Alexeev081 [22]3 years ago
3 0
We can solve this problem by calculating the individual rate of working and equate it to their total rate of working.

If Dave can complete a sales route in 4 hours, then his working rate is

\frac{1}{4}

Also, if James can do it in 5 hours, then his working rate is

\frac{1}{5}

Let
x
be the hours that both will use to complete the sales route,

Then rate at which both completes this task is
\frac{1}{x}


Meaning if we add their individual rates we should get

\frac{1}{x}

That is;

\frac{1}{4} + \frac{1}{5} = \frac{1}{x}

The LCM is
20x

So let us multiply through with the LCM.

20x \times \frac{1}{4} + 20x \times \frac{1}{5} =20x \times \frac{1}{x}

5x + 4x = 20

We simplify to get,

9x = 20

Dividing through by 9 gives;

x = \frac{20}{9}

x = 2\frac{1}{9}

Therefore the two will complete sales route in
2 \frac{1}{9}
hours.
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Step 2: Substitute:<span> 
</span><span><span>8<span><span>(<span>25/16</span>)^</span>2</span>=25(<span>x^2</span>−<span>y^2</span>)
</span><span>8<span><span>(<span>25/16</span>)^</span>2</span>=25(<span>x^2</span>−<span>y^2</span>)</span></span>
</span><span>x^2</span>−<span>y^2</span>=<span>25/32</span><span>.

Add [2] and [3]:<span> 
</span><span>2<span>x^2</span>=<span>75/32
</span><span>x^2</span>=<span>75/74</span></span>
<span>x=±5</span></span>√3/8<span>
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</span>
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If cos(x) = Three-fourths and tan(x) &lt; 0, what is cos(2x)?
makvit [3.9K]

Step-by-step explanation:

The value of sin(2x) is \sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

8

15

How to determine the value of sin(2x)

The cosine ratio is given as:

\cos(x) = -\frac 14cos(x)=−

4

1

Calculate sine(x) using the following identity equation

\sin^2(x) + \cos^2(x) = 1sin

2

(x)+cos

2

(x)=1

So we have:

\sin^2(x) + (1/4)^2 = 1sin

2

(x)+(1/4)

2

=1

\sin^2(x) + 1/16= 1sin

2

(x)+1/16=1

Subtract 1/16 from both sides

\sin^2(x) = 15/16sin

2

(x)=15/16

Take the square root of both sides

\sin(x) = \pm \sqrt{15/16

Given that

tan(x) < 0

It means that:

sin(x) < 0

So, we have:

\sin(x) = -\sqrt{15/16

Simplify

\sin(x) = \sqrt{15}/4sin(x)=

15

/4

sin(2x) is then calculated as:

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So, we have:

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4

15

∗

4

1

This gives

\sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

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