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dem82 [27]
2 years ago
11

What's the most effective method for controlling inventory ? a ) Electronically , by reviewing billing receipts b ) Electronical

ly , by checking recent orders Oc ) Visually , by looking at discarded packaging d ) Visually , by looking at what's on the shelf
Mathematics
1 answer:
mina [271]2 years ago
8 0

Answer:

a ) Electronically , by reviewing billing receipts

Step-by-step explanation:

The main purpose of controlling inventory is to make sure that the optimal amount of products are being kept.

Therefore, option A is correct.

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A farmer plants apple, pear and cherry trees
gogolik [260]
? is there any more context to the question?
8 0
3 years ago
A​ country's people consume 6.6 billion pounds of candy​ (excluding chewing​ gum) per year. Express this quantity in terms of po
german
<span>A​ country's people consume 6.6 billion pounds of candy​ (excluding chewing​ gum) per year. Population of the country is 303 million. Specific consumption, = ((6.6*10^9 pounds)/( year* 303*10^6 persons))*(year/ 12 months) =1.8 pounds/(months*persons)</span>
4 0
4 years ago
Solve the system by graphing. Write the solution as an ordered pair.
storchak [24]

Answer:

the answer to the question is - 2 over 7 and - 12 over 7

8 0
4 years ago
An oil exploration firm is formed with enough capital to finance ten explorations. The probabil- ity of a particular exploration
tensa zangetsu [6.8K]

Answer:

μ = 1 The firm expects that one oil exploration will be successful.

v(x)= 0.9

Step-by-step explanation:

The first step is to define the random variable x as:

x: number of oil explorations being succesful

Then x can be take this values:

x = 0 , x =1 ... x =10

x is a binomially distributed random variable with parameters.

p = 0.1 and  n=10

And the mean or the expected value of x is:

μ = E(x) = np

Then μ = 10*0.1 = 1

And the variance of x is:

V(x) = np(1-p)

V(x) = 10(0.1)(1-0.1)= 0.9

6 0
3 years ago
What sample size is needed to give a margin of error within +-6 in estimating a population mean with 95% confidence, assuming a
rodikova [14]

Answer:

43

Step-by-step explanation:

The formula for Margin of Error =

Margin of Error = z × standard deviation/√n

Margin of Error= ± 6

z = z score of 95% Confidence Interval is 1.96

s = 20

n = sample size

±6 = 1.96 × 20/√n

Cross Multiply

±6 × √n = 1.96 × 20

±6 × √n = 39.2

Divide both sides by ±7

√n = 39.2/±6

√n = 6.5333333333

Square both sides

n = 6.5333333333²

n= 42.684444444

Rounding up to the nearest integer = 43

4 0
3 years ago
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