Answer:
sin(A-B) = 24/25
Step-by-step explanation:
The trig identity for the differnce of angles tells you ...
sin(A -B) = sin(A)cos(B) -sin(B)cos(A)
We are given that sin(A) = 4/5 in quadrant II, so cos(A) = -√(1-(4/5)^2) = -3/5.
And we are given that cos(B) = 3/5 in quadrant I, so sin(B) = 4/5.
Then ...
sin(A-B) = (4/5)(3/5) -(4/5)(-3/5) = 12/25 + 12/25 = 24/25
The desired sine is 24/25.
Answer:
It is an open circuit, yes
Step-by-step explanation:
Answer:
I think it's (0,-3)
Step-by-step explanation:
The two sixes cancel out and -5--2 is -3 :)
greater
less
less
equal
absolute val of 4
I am guessing your problem should read...
A) n = -5n + 90 (isolate the variables by adding 5n to each side)
+5n +5n
6n = 90 (since we don't want to know what 6n's are worth, divide by 6)
6n/6 = 90/6
n = 15