(1) R+G+B=50
(2) R=B+6
(3) G=B-4 so substitute G in (1)
R+B-4+B=50 substitute (2) in here
B+6+B-4+B=50 group like terms and solve
3B+2=50
3B=50-2
B=48/3=16 substitute in (2) and (3)
R=16+6=22
G=16-4=12
Check
22+12+16=50✅
Answer:
Step-by-step explanation:
36 / 3.6 = 10
36 / 4 = 9
Answer:
Step-by-step explanation:
5(m-3)≥7m-2.4
5m-15≥7m-2.4
2m≤-12.6
m≤-6.1
