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sergeinik [125]
3 years ago
9

3k^2-11k-4=0 solve with quadratic formula

Mathematics
1 answer:
lawyer [7]3 years ago
8 0
It should be k= 4 or -1/3
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Christina made 84% of all shots attempted and mallory made 7/8 of all shots who made more
Ghella [55]

Hey!

--------------------------------------------------

~Turn both into decimals.

84% = 0.84

7/8 = 0.875

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Hence, Mallory made more shots then Christina!

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Hope This Helped! Good Luck!

6 0
3 years ago
Find the values of b <br>b²= 256<br>b=?​
ehidna [41]

Answer:

if b²=256

then b=16

....................

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2 years ago
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From a pack of 9 cards numbered 1-9, three cards are drawn at random and laid on a table from left to right.
Andreas93 [3]
Answer: 1/6
Explanation: Since we need to draw three cards from a pack of 9 and the digits require an order, then our sample space becomes: 9P3.
Now, we don't care about picking an order when picking three cards to analyse, as there is only 1 way in arranging the three cards in descending order.

Thus, we get:

\frac{^{9}C_3}{^{9}P_3} = \frac{1}{6}
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What are the solutions to the quadratic equation below?<br> 4x^2 + 28x + 49 = 5
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2 years ago
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How do you add vectors? Add the vector &lt;3,4&gt; to the vector that goes 7 units at an angle of 2π/3.
lawyer [7]

Answer:

The sum of the two vectors is the vector <-0.5 , 4+3.5\sqrt{3} >

Step-by-step explanation:

The horizontal component (x) of a vector whose magnitude is b units and its direction is Ф° is b cos Ф

The vertical component (y) of a vector whose magnitude is b and its direction is Ф is b sin Ф

The vector is <b cos Ф , b sin Ф>

∵ The vector goes 7 units at an angle \frac{2\pi }{3}

- That means its magnitude is 7 and its direction is  \frac{2\pi }{3}

∴ x = 7 cos(  \frac{2\pi }{3} )

∴ y = 7 sin(  \frac{2\pi }{3} )

∵ cos(  \frac{2\pi }{3} ) =  -\frac{1}{2}

∵ sin(  \frac{2\pi }{3} ) =  \frac{\sqrt{3}}{2}

- Substitute them in x and y

∴ x = (7)( -\frac{1}{2} )

∴ x = -3.5

∴ y = (7)( \frac{\sqrt{3}}{2} )

∴ y = 3.5\sqrt{3}

∴ The vector is <-3.5 , 3.5\sqrt{3}>

Now lets add the vectors by adding xs and ys components

∵ <3 , 4> + <-3.5 , 3.5\sqrt{3} > = <3 + -3.5 , 4 + 3.5\sqrt{3} >

∴  <3 , 4> + <-3.5 , 3.5\sqrt{3}> = <-0.5 , 4+3.5\sqrt{3} >

∴ The sum of the two vectors is the vector <-0.5 , 4+3.5\sqrt{3} >

5 0
3 years ago
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