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Sidana [21]
2 years ago
9

What are your zodiac signs?

Mathematics
2 answers:
SSSSS [86.1K]2 years ago
3 0
My zodiac sign is a virgo
:)
Show the chart when it’s done
If it’s not done yet
Kazeer [188]2 years ago
3 0

Answer:

I'm a Gemini

Step-by-step explanation:

Aries, Taurus, Gemini, Cancer, Leo, Virgo, Libra, Scorpio, Sagittarius, Capricorn, Aquarius and Pisces.
Those are all of the 12 signs.

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-1.2<br> 29<br> 20<br> Enter the answer as an exact decimal or simplified fraction
Rudiy27

Answer:

ohh

Step-by-step explanation:

6 0
3 years ago
The measures of 6 of the interior angles of a heptagon are: 120°, 150°, 135°, 170°, 90°, and 125°. What is the measure of the la
Lilit [14]
1. consider one angle of a (convex) heptagon. From that angle you can construct 7-3=4 diagonals. (-3 because we cannot create diagonals with the adjacent vertices and the angle itself )

2. 4 diagonals create 5 triangular regions. (check the picture)

3. So the sum of the measures of the interior angles of the heptagon is 180°*5=900°.

4. The measure of the remaining 7th interior angle is 900°-(120+150+135+170+90+125)°=110°.

5. The largest exterior angle is when the interior angle is the smallest.

6. The smallest interior angle is 90°, so the largest exterior angle is 180°-90°=90°


Answer: 90°

7 0
3 years ago
In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .
spayn [35]

Answer:

74.0°

Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the  nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

\frac{k}{sin(K)}=\frac{j}{sin(J)}   \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)}  \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o  \\

6 0
3 years ago
At 4:00 am, the outside temperature was -28*F. By 4:00 P.M. it rose 38 degrees. What was the temperature at 4:00 P.M. ?
andreyandreev [35.5K]
The answer would be 10 degrees
i hope this helps
7 0
3 years ago
I need help on question 12 asap!! My assignment is due in 20 minutes and I still got other problems to solve.
Lorico [155]
$2.27:) hope this helps!!
4 0
3 years ago
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