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Mars2501 [29]
3 years ago
12

Where is the hole for the following function located?

Mathematics
1 answer:
Sholpan [36]3 years ago
5 0
The hole of a function is described as the x-y coordinate wherein the denominator and numerator equates to zero. For the function f(x)= x+3/(x+4)(x+3), the common polynomial given is x-3 which can be equated to zero. Hence, 0 divided 0 means a hole in the function. If x+3 = 0, the hole of the function is at x = -3. ^w^
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What is the simplest form for 9/72
Marat540 [252]
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Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC
e-lub [12.9K]

Answer:

DC=\frac{8}{3}\ units

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

so

<em>In the right triangle ABM</em>

Applying the Pythagorean Theorem

BM^2=AB^2-AM^2

we have

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substitute

BM^2=5^2-x^2

BM^2=25-x^2 -----> equation A

<em>In the right triangle BMC</em>

Applying the Pythagorean Theorem

BM^2=BC^2-MC^2

we have

BC=7\ units\\MC=AC-AM=(9-x)\ units

substitute

BM^2=7^2-(9-x)^2

BM^2=49-(81-18x+x^2)  

BM^2=49-81+18x-x^2

BM^2=-x^2+18x-32 ----> equation B

equate equation A and equation B

-x^2+18x-32=25-x^2

solve for x

18x=25+32\\18x=57\\\\x=\frac{57}{18}

Simplify

x=\frac{19}{6}

<em>Find the length of DC</em>

DC=AC-2x

substitute the given values

DC=9-2(\frac{19}{6})

DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units

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Answer:

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Step-by-step explanation:

Convert 12/17 to decimal by dividing the numerator by denominator.

12 ÷ 17 = 0.70588.......

The nearest thousandth is the third decimal place.

If we round up: 0.706

If we round down: 0.705

Because the fourth digit is "8", we round up.

If the digit after the one you want to round to is 5 or greater, then you round up. If the digit after is 4 or less, round down..

12 ÷ 17 = 0.70588....... ≈ 0.706

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