Where is the hole for the following function located?
1 answer:
You might be interested in
Answer:
y = x² - x +
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k) = (1, 3 ), thus
y = a(x - 1)² + 3
To find a substitute (- 1, 5) into the equation
5 = a(- 1 - 1)² + 3 ( subtract 3 from both sides )
2 = 4a ( divide both sides by 4 )
a = , thus
y = (x - 1)² + 3 ← expand factor using FOIL
y = (x² - 2x + 1) + 3 ← distribute parenthesis
= x² - x +
+ 3
= x² - x +