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2 years ago

Where is the hole for the following function located?

1 answer:

5 0

The hole of a function is described as the x-y coordinate wherein the denominator and numerator equates to zero. For the function f(x)= x+3/(x+4)(x+3), the common polynomial given is x-3 which can be equated to zero. Hence, 0 divided 0 means a hole in the function. If x+3 = 0, the hole of the function is at x = -3. ^w^

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On Monday, Torrance practiced the violin for 4/10 of an hour. On Tuesday, he practiced for 1 6/8 of an hour. How much time did h

Yuri [45]

Answer: $2\frac{3}{20}$

Step-by-step explanation:

First, convert mixed numbers into improper fractions and simplify all fractions

$\frac{4}{10}$ ÷ $\frac{2}{2}$ = $\frac{2}{5}$

$1\frac{6}{8}$ = $\frac{8(1) + 6}{8}$ = $\frac{14}{8}$ ÷ $\frac{2}{2}$ = $\frac{7}{4}$

Next, find their sum. Remember to find the LCD and convert the fractions so they have like denominators.

Monday + Tuesday = Total

$\frac{2}{5}$ + $\frac{7}{4}$ = Total the LCD of 5 and 4 is 20

$(\frac{4}{4})\frac{2}{5}$ + $(\frac{5}{5})\frac{7}{4}$ = Total

$\frac{8}{20}$ + $\frac{35}{20}$ = Total

$\frac{43}{20}$ = Total

Then, convert the improper fraction into a mixed number

$\frac{43}{20}$ = $2\frac{3}{20}$

7 0

3 years ago

What is the missing number in this pattern? 0, 2, 6, ----, 30, 62

mario62 [17]

Answer:

Step-by-step explanation:

so the pattern is they add 2 then they add 4 then they add 8 then the add 16 basically they are double the number being added each number so the missing number is 14

5 0

2 years ago

Read 2 more answers

Help needed on this composition math problem

Marrrta [24]

Given that f(x) = x/(x - 3) and g(x) = 1/x and the application of function operators, f ° g (x) = 1/(1 - 3 · x) and the domain of the resulting function is any real number except x = 1/3.

<h3>How to analyze a composed function</h3>

Let be f and g functions. Composition is a binary function operation where the variable of the former function (f) is substituted by the latter function (g). If we know that f(x) = x/(x - 3) and g(x) = 1/x, then the composed function is:

$f\,\circ\,g \,(x) = \frac{\frac{1}{x} }{\frac{1}{x}-3}$

$f\,\circ\,g\,(x) = \frac{\frac{1}{x} }{\frac{1-3\cdot x}{x} }$

$f\,\circ\,g\,(x) = \frac{1}{1-3\cdot x}$

The domain of the function is the set of x-values such that f ° g (x) exists. In the case of rational functions of the form p(x)/q(x), the domain is the set of x-values such that q(x) ≠ 0. Thus, the domain of f ° g (x) is $\mathbb{R} - \{\frac{1}{3} \}$ .