Answer:
Graphs behave differently at various x-inter cepts. Sometimes the graph will cross over the x-axis at an intercept. Other times the graph will touch the x-axis and bounce off.
Suppose, for example, we graph the function. f(x) = (x+3)(x - 2)²(x+1)³.
Notice in the figure below that the behavior of the function at each of the x-intercepts is different.
Answer:
f=10
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given the data:
Weight ____Height
110 _______ 120
130 _______140
150 _______160
From the data given, we can conclude that that there exist a positive relationship between weight and height. As weight increases, the height increases and vice versa. The weight variable and height variable are positively correlated and thus an individual with a high weight value will have a high height value.
Answer:
75 degrees
Step-by-step explanation:
I know the measure of the triangle's third angle is 75 degrees because all the angles of a triangle add up to 180 degrees. So, I did 180-62-43 and got 75. So, in order for this triangle to be true, the third triangle would have to be 75 degrees.
To check: 43 degrees+ 62 degrees+ 75 degrees = 180 degrees.
Using a discrete probability distribution, it is found that:
a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.
b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.
c) The expected value is of 1.3 lawns mowed on a randomly selected day.
<h3>What is the discrete probability distribution?</h3>
Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:
Item a:
P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.
Item b:

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.
Item c:
The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:
E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.
The expected value is of 1.3 lawns mowed on a randomly selected day.
More can be learned about discrete probability distributions at brainly.com/question/24855677