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TiliK225 [7]
2 years ago
13

Can someone please help me on this?:)​

Mathematics
1 answer:
Bingel [31]2 years ago
7 0

Answer:

First blank: 10

Second blank: 1

Step-by-step explanation:

For both i used an online converter:

Please check attachments

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user100 [1]
200+400=600 u just add 2 and 6 togather and u get 6 and then annd the two zeros on too it 
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3 years ago
Solve the equation. 6x−7=2x+13
Sergio [31]

Answer:

6x - 7 = 2x + 13

6x - 2x = 13 + 7

4x = 20

x = 20/4

x = 5

Hope it helps!

8 0
3 years ago
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Please help me get this right I don’t know how to do it.
velikii [3]

Answer:

tan∠E=1/3

Step-by-step explanation:

Tangent or opposite/adjacent of angle E is segment HF/3 to solve for HF you can use sine of H opposite over hypotenuse or √8/HF=sin45°. Rearranging the equation you get √8/sin45°=HF and sin45°= 2√2 so √8/2√2=1 HF=1 now you know that tan(∠E)=1/3.

7 0
2 years ago
How to find the base and altitude of a rectangle if its area is 70 and its perimeter is 34?
kicyunya [14]

The area of a rectangle is base * altitude, and the perimeter is 2*base + 2*altitude,



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6 0
3 years ago
How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo
kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

s = \frac{d}{t}

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so s = 299,792.458

(a) San Francisco (about 500km)

Find t when d = 500. So

s = \frac{d}{t}

299,792.458 = \frac{500}{t}

299,792.458t = 500

t = \frac{500}{299,792.458}

t = 0.0017s

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when d = 10,000. So

s = \frac{d}{t}

299,792.458 = \frac{10,000}{t}

299,792.458t = 10,000

t = \frac{10,000}{299,792.458}

t = 0.033s

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when d = 400,000. So

s = \frac{d}{t}

299,792.458 = \frac{400,000}{t}

299,792.458t = 400,000

t = \frac{400,000}{299,792.458}

t = 1.334s

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that d = 44,879,361.3. So:

s = \frac{d}{t}

299,792.458 = \frac{44,879,361.3}{t}

299,792.458t = 44,879,361.3

t = \frac{44,879,361.3}{299,792.458}

t = 149.7s

It takes 149.7s for the light to reach Venus.

3 0
3 years ago
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