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Ede4ka [16]
2 years ago
14

Sau 18 tháng, số tiền nợ cả gốc lẫn lãi phải trả là $5200. Số tiền gốc là bao nhiêu nếu lãi suất đơn là 8%/năm?

Mathematics
1 answer:
defon2 years ago
4 0

Answer:

$5836.32

Step-by-step explanation:

5200 \times  {1.08}^{1.5}

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A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. ​(a) Describe the
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Answer:

a) \bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

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\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

b) z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

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c) z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

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Step-by-step explanation:

For this case we know the following propoertis for the random variable X

\mu = 83, \sigma = 27

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

Part b

We want this probability:

P(\bar X>89)

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 89 we got:

z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

Part c

P(\bar X

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 75.65 we got:

z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

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Part d

We want this probability:

P(79.4 < \bar X < 89.3)

We find the z scores:

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