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2 years ago

11

How can i solve integral parts

" title="integral of e ^2 sin(3) " alt="integral of e ^2 sin(3) " align="absmiddle" class="latex-formula">

2 answers:

Vesnalui [34]2 years ago

5 0

$f (e² sin (3))$

integrate it :

$→ \frac{1}{2 + 1} e²(-cos(3x))$

add constant:

$→\frac{ {e}^{2} }{3} cos(3x)+c$

yulyashka [42]2 years ago

4 0

Answer:

$-\frac{e^2}{3} cos(3x) +c$

Explanation:

$\int \left(e^2sin\left(3\right)\right)$

integrate it :

$\frac{1}{2+1}e^2 (- cos(3x))$

add constant:

$-\frac{e^2}{3} cos(3x) +c$

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There are 100,000,000 pennies in one million dollars.

Step-by-step explanation:

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How much would you need to deposit in an account now in order to have $2,500 in the account in 6 years? Assume the account earns

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Simple interest is computed using ...

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3 years ago

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Answer:

263.76 m^3

Step-by-step explanation:

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2 years ago

A bird sees a worm on the ground 50 m. below. The bird dives for the worm at a speed of 6 m/sec. The function h\left( t \right)

iragen [17]

<u>Given</u>:

The height of the bird at time t is given by the function $h(t)=-4.9t^2+6t+50$

We need to determine the time it takes the worm to be eaten by the bird.

<u>Time taken:</u>

The time can be determined by substituting h(t) = 0 in the function.

Thus, we have;

$0=-4.9t^2+6t+50$

Switch sides, we get;

$-4.9t^2+6t+50=0$

Let us solve the equation using the quadratic formula.

Thus, we get;

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Simplifying, we get;

$t=\frac{-6 \pm \sqrt{36+980}}{-9.8}$

$t=\frac{-6 \pm \sqrt{1016}}{-9.8}$

$t=\frac{-6 \pm 31.87}{-9.8}$

The values of t are given by

$t=\frac{-6 + 31.87}{-9.8}$ and $t=\frac{-6 - 31.87}{-9.8}$

$t=\frac{25.87}{-9.8}$ and $t=\frac{-37.87}{-9.8}$

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Since, the value of t cannot be negative, then $t=3.9$

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