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dybincka [34]
2 years ago
14

PLEASE HELP NO LINKS, MAY PIN FILES, OR TYPE BOX THANK YOU FOR ANSWER​

Mathematics
1 answer:
lilavasa [31]2 years ago
6 0

Answer:

1. Paul has mixed up the translation of the ordered pair.

New location: (1, 5)

2. Option C :  E = (3, 2)  F = (8, 4)  G = (5, 7)

Step-by-step explanation:

An ordered pair is a pair of numbers, (x,y) , written in a particular order.

It is often used to represent a point on a coordinate plane.

1.  From inspection of the diagram, the market is located at (3, 8)

Paul's mistake is that he has mixed up the translation of the ordered pair.  He has moved the market 3 to the left and 2 units down instead of the required 2 to the left and 3 units down.

The correct ordered pair for the new location of the market is (1, 5)

2. For each coordinate point (x, y), the first number is the x-coordinate (along the x-axis) and the second number is the y-coordinate (along the y-axis).  

E = (3, 2)

F = (8, 4)

G = (5, 7)

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\sqrt[7]{x^{4}}

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(\sqrt[7]{x})^{4}

Step-by-step explanation:

we have

x^{\frac{4}{7}}

Remember the properties

\sqrt[n]{a^{m}}=a^{\frac{m}{n}}

(a^m)^{n}=a^{m*n}

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<u><em>Verify each case</em></u>

Part 1) we have

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we know that

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Compare with the given expression

x^{\frac{7}{4}} \neq x^{\frac{4}{7}}

Part 2) we have

\sqrt[7]{x^{4}}

we know that

\sqrt[7]{x^{4}}=x^{\frac{4}{7}}

Compare with the given expression

x^{\frac{4}{7}} = x^{\frac{4}{7}}

therefore

Is equivalent to the given expression

Part 3) we have

(x^{\frac{1}{7}})^{4}

we know that

(x^{\frac{1}{7}})^{4}=x^{\frac{4}{7}}

Compare with the given expression

x^{\frac{4}{7}} = x^{\frac{4}{7}}

therefore

Is equivalent to the given expression

Part 4) we have

(x^{\frac{1}{4}})^{7}                      

we know that

(x^{\frac{1}{4}})^{7}=x^{\frac{7}{4}}

Compare with the given expression

x^{\frac{7}{4}} \neq x^{\frac{4}{7}}

Part 5) we have

(\sqrt[4]{x})^{7}

we know that

(\sqrt[4]{x})^{7}=(x^{\frac{1}{4}})^{7}=x^{\frac{7}{4}}

Compare with the given expression

x^{\frac{7}{4}} \neq x^{\frac{4}{7}}

Part 6) we have

(\sqrt[7]{x})^{4}

we know that

(\sqrt[7]{x})^{4}=(x^{\frac{1}{7}})^{4}=x^{\frac{4}{7}}

Compare with the given expression

x^{\frac{4}{7}} = x^{\frac{4}{7}}

therefore

Is equivalent to the given expression

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