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NARA [144]
2 years ago
9

The plan for the Thorne’s backyard play area, shaped like a trapezoid, is shown. The area of the play area is 286.56 square feet

. A border is planned around the perimeter of the play area. How many feet of material are needed for the border?
Mathematics
1 answer:
lorasvet [3.4K]2 years ago
6 0

The length of material needed for the border is the perimeter of the backyard play area

<h3>How to calculate the length of material needed </h3>

The area of the play area is given as:

Area = 286.56

The area of a trapezoid is calculated using:

Area = 0.5 * (L1 + L2) * H

Where L1 and L2, are the parallel sides of the trapezoid and H represents the height.

The given parameter is not enough to solve the length of material needed.

So, we make use of the following assumed values.

Assume that the parallel sides are: 25 feet and 31 feet long, respectively.

While the other sides are 10.2 feet and 8.2 feet

The length of material needed would be the sum of the above lengths.

So, we have:

Length = 25 + 31 + 10.2 + 8.2

Length = 74.4

Using the assumed values, the length of material needed for the border is 74.4 feet

Read more about perimeters at:

brainly.com/question/17297081

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Fill in the blanks to complete the area model to solve 6.60 divided by 15 is the same as _ x ? = _ 6.60 = _ hundredths
storchak [24]

Answer:

15 x = 6.60

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Step-by-step explanation:

Given

\frac{6.60}{15}

Required

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\frac{6.60}{15}

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15 * x = \frac{6.60}{15} * 15

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Recall that:

x = \frac{6.60}{15}

x = 0.44

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3 years ago
How much of the garage foot is white
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alexandr402 [8]

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3 0
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Which of the following equations represents the perpendicular bisector of WX graphed below?
kotykmax [81]
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Nex, we find the slope of the line containing M, perpendicular to WX. We know that if m and n are the slopes of 2 parallel lines, then mn=-1.

The slope of WX is \displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{2-(-4)}{-5-5}= \frac{6}{-10}= -\frac{3}{5}.

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