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Ahat [919]
2 years ago
11

1. If the area of a circle is 81pi square feet, find its circumference.

Mathematics
1 answer:
My name is Ann [436]2 years ago
4 0

Answer:

the circumference is 18 pi feet.

Step-by-step explanation:

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I need help with this
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X represents The value of players on the field

Step-by-step explanation:

the numbers 0-11 are showing how many people would be on the field should an official game be played

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2 years ago
While shopping, Dawn finds a backpack that she likes on the sale rack. Its original price is $60,
Nadya [2.5K]

No. Because 33 $ is the money deducted from the 60 $. Dawn bought everything for less than 60 $.

So, if Dawn purchases everything on the rack with a 30% discount and 15% coupon the total will indeed make 45%.

We have to take 100% - 45%= 55% to know the reduction number. Let's proceed to the calculations now.

100%= 60 $

1%=60/100

55%= 60/100 × 55 = 33 $

Now <u>NOTE</u><u>;</u><u> </u><u>33</u><u> </u><u>$</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>money</u><u> </u><u>reduced</u><u> </u><u>from</u><u> </u><u>the</u><u> </u><u>60</u><u> </u><u>$</u><u>.</u><u> </u><u>So</u><u>,</u><u> </u><u>logically</u><u>,</u><u> </u><u>33</u><u> </u><u>$</u><u> </u><u>isn't</u><u> </u><u>the</u><u> </u><u>amount</u><u> </u><u>which</u><u> </u><u>Dawn</u><u> </u><u>purchased</u><u> </u><u>the</u><u> </u><u>whole</u><u> </u><u>rack</u><u>. </u>

To find the amount at which she purchased everything, we need to do,

60 $ - 33 $ = 27 $

6 0
3 years ago
If M is the midpoint of PQ and X is the midpoint of PM then PX = a PQ
tino4ka555 [31]

Answer:

found this i think this should help with your question

Step-by-step explanation:

Download pdf
3 0
3 years ago
PLSSS<br><br> C= <img src="https://tex.z-dn.net/?f=%5Cfrac%7B12%5E%7B3%7D%20.%206%5E%7B5%7D%20%7D%7B9%5E%7B4%7D%20.%202%5E%7B10%
Rudiy27

Answer:

2

Step-by-step explanation:

The trick here is to reduce each of the bases to lowest form first

12 = 3.4 = 3 .2.2  = 3.2^{2}\\12^{3}  = (3.2^{2} )^{3} = 3^{3}2^{6}  \\6 = 3.2\\6^{5} = (3.2)^{5} = 3^{5} .2^{5} \\\\Numerator = 3^32^63^52^5 = 3^82^{11}\\Denominator computation\\9 = 3^2\\9^{4} = (3^{2} )^4 = 3^{8} \\Denominator = 3^82^{10} \\\\\frac{Numerator}{Denominator }  =\frac{{3^8}{2^{11} }}{3^82^{10}} = \frac{2^{11}} {2^{10}} = 2^1 = 2  

7 0
2 years ago
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