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Fynjy0 [20]
3 years ago
12

The product of (n2 – 6n + 3) and -4n is________ When this product is multiplied by -n, the result is________

Mathematics
2 answers:
krek1111 [17]3 years ago
3 0
-4n^3+24n^2-12n, 4n^4-24n^3+12n^2
aivan3 [116]3 years ago
3 0

Answer:

The product of (n2 – 6n + 3) and -4n is <u>-4n^3+24n^2-12n</u>. When this product is multiplied by -n, the result is <u>4n^4-24n^3+12n^2</u>.

Step-by-step explanation:

We have been given an incomplete statement. We are supposed to fill in the blanks for our given statement.

First of all, we will find product of (n^2-6n+3) and -4n.

-4n(n^2-6n+3)

Using distributive property a(b+c)=ab+ac, we will get:

-4n*n^2-4n*-6n-4n*3

-4n^3+24n^2-12n

Therefore, the expression for 1st blank is -4n^3+24n^2-12n.

Now, we will find product of (-4n^3+24n^2-12n) and -n.

-n(-4n^3+24n^2-12n)

Using distributive property again a(b+c)=ab+ac, we will get:

-n*-4n^3-n*24n^2-n*-12n)

4n^4-24n^3+12n^2

Therefore, the expression for 2nd blank is 4n^4-24n^3+12n^2.

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<h3>Answer:   15x^(7/3) - 8x^(7/4) + x + 9000</h3>

=========================================================

Explanation:

If you know the cost function C(x), to find the marginal cost, we apply the derivative.

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\text{Cost} = \text{antiderivative of marginal cost}\\\\\displaystyle C(x) = \int \left(35x^{4/3} - 14x^{3/4} + 1\right)dx\\\\

C(x) = \frac{1}{1+4/3}*35x^{4/3+1} - \frac{1}{1+3/4}*14x^{3/4+1} + x + D\\\\C(x) = \frac{1}{7/3}*35x^{7/3} - \frac{1}{7/4}*14x^{7/4} + x + D\\\\C(x) = \frac{3}{7}*35x^{7/3} - \frac{4}{7}*14x^{7/4} + x + D\\\\C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

D represents a fixed constant. I would have used C as the constant of integration, but it's already taken by the cost function C(x).

To determine the value of D, we plug in x = 0 and C(x) = 9000. This is because we're told the fixed costs are $9000. This means that when x = 0 units are made, you still have $9000 in costs to pay. This is the initial value. You'll find that all of this leads to D = 9000 because everything else zeros out.

Therefore, we go from this

C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

to this

C(x) = 15x^{7/3} - 8x^{7/4} + x + 9000\\\\

which is the final answer.

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