For 11a its 2:10 because how you would come up with it is by placing pablos free minutes first and then putting pablos paid minutes and 11b is8:25 because once again you would place sams free minutes first and then his paid minutes
Answer:
Ok so here are the simple rules of doing it (very easy) cause I’m not doing it all so . when multiplying a power with The same base keep the base but add the exponents. Dividing, keep the base (if their the same if not then its already simplified same with multiplication) but SUBTRACT the exponents. Also keep the parenthesis if it’s a negative number base.
I’ll do a few.
11) a^10. 11b) 5^4
12) (-2)^2.
13) 10^2. 13b) s^6
14) -4s^5(t^6) <- [Im not sure of this one)
15) x^3(y^3)
<h3>Given:</h3><h3>Large cone:</h3>
<h3>Small cone:</h3>
<h3>Note that:</h3>
<h3>To find:</h3>
- The volume of the frustum of the given cone.
<h3>Solution:</h3>
- Frustum is a part of a cone formed by cutting off the top by a parallel plane.
Let's solve!
First, let's find the volume of the smaller cone.
Substitute the values according to the
formula.
Now, we can round off to the nearest hundredth.
The value in the thousandths place is smaller than 5 so we won't have to round up.
Next, let's find the volume of the bigger cone.
Substitute the values according to the formula.
Now, we can round off to the nearest hundredth.
The value in thousandths place is smaller than 5 so we won't have to round up.
Now, we can find the volume of the frustum.
We'll have to minus the volume of the smaller cone from the bigger cone.
<u>Hence, the volume of the frustum is 1172.86 cubic centimeters.</u>
Multiply the original DE by xy:
xy2(1+x2y4+1−−−−−−−√)dx+2x2ydy=0(1)
Let v=xy2, so that dv=y2dx+2xydy. Then (1) becomes
x(y2dx+2xydy)+xy2x2y4+1−−−−−−−√dxxdv+vv2+1−−−−−√dx=0=0
This final equation is easily recognized as separable:
dxxln|x|+CKxvKx2y2−1K2x4y4−2Kx2y2y2=−dvvv2+1−−−−−√=ln∣∣∣v2+1−−−−−√+1v∣∣∣=v2+1−−−−−√+1=x2y4+1−−−−−−−√=x2y4=2KK2x2−1integrate both sides
Answer:
(-2, 2)
Step-by-step explanation:
Take point (3, 2) and first translate it left one unit. Now the point is (2, 2)
Now reflect it over the y-axis. Doing so keeps the y value the same, we have a vertical line of reflection, so we are only changing the distance to the y-axis, which is the x-value.
Our x value is 2 units away from the y axis, so its reflection will be 2 units away on the other side of the axis.
The new x value is -2, so the point is (-2, 2)
